Find the mean of each data set. 11,16,17,20,26

What Is 2(2x-5)=3x+x-2x ?

oksano4ka [1.4K]

Answer:

x = 5

Step-by-step explanation:

Solve for x:

2 (2 x - 5) = 3 x + x - 2 x

3 x + x - 2 x = 2 x:

2 (2 x - 5) = 2 x

Divide both sides by 2:

2 x - 5 = x

Subtract x from both sides:

(2 x - x) - 5 = x - x

2 x - x = x:

x - 5 = x - x

x - x = 0:

x - 5 = 0

Add 5 to both sides:

x + (5 - 5) = 5

5 - 5 = 0:

Answer: x = 5

7 0

3 years ago

Read 2 more answers

Comparing Theater Sales<br> I need help A.S.A.P!!!

Yuki888 [10]

Step-by-step explanation:

oh come on ! you can see that with common sense : it is 2)

while the data itself is the same, but in figure B it is kind of suggested that "Super Cinema" had twice the sales of "Bud's Movies". which is not the case at all.

and that is one of the problems, when you don't show the whole data range (which happens when you don't start the data range at the actual beginning - like 0 in this case).

as I keep saying : never trust a statistic you have not falsified yourself ...

4 0

2 years ago

A bacteria culture starts with 400 bacteria and grows at a rate proportional to its size. After 4 hours, there are 9000 bacteria

Kaylis [27]

Answer:

A) The expression for the number of bacteria is $P(t) = 400e^{0.7783t}$ .

B) After 5 hours there will be 19593 bacteria.

C) After 5.55 hours the population of bacteria will reach 30000.

Step-by-step explanation:

A) Here we have a problem with differential equations. Recall that we can interpret the rate of change of a magnitude as its derivative. So, as the rate change proportionally to the size of the population, we have

$P' = kP$

where $P$ stands for the population of bacteria.

Writing $P'$ as $\frac{dP}{dt}$ , we get

$\frac{dP}{dt} = kP$ .

Notice that this is a separable equation, so

$\frac{dP}{P} = kdt$ .

Then, integrating in both sides of the equality:

$\int\frac{dP}{P} = \int kdt$ .

We have,

$\ln P = kt+C$ .

Now, taking exponential

$P(t) = Ce^{kt}$ .

The next step is to find the value for the constant $C$ . We do this using the initial condition $P(0)=400$ . Recall that this is the initial population of bacteria. So,