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3 years ago

Which expression is equivalent to 5^4(5^-^3)^2? 5^1 5^2 1/5^1 1/5^2

Mathematics

1 answer:

inessss [21]3 years ago

8 0

Answer:

1 5th ^2.

Step-by-step explanation:

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Using the graph of f(x) = log2x below, approximate the value of y in the equation 22y = 5.

Naddika [18.5K]

The correct question is
Using the graph of f(x) = log2x below, approximate the value of y in the equation 2^(2y) = 5

we have
2^(2y) = 5--------------> applying base 2 logarithm both members
2y*log2(2)=log2(5)
log2(2)=1
then
2y=log2(5)
y=[log2(5)]/2

using the graph
for x=5 the approximate value of log2(5) is 2.3
see the attached figure
so
y=[log2(5)]/2--------> y=[2.3]/2----------> y=1.15

the answer is
the approximate value of y is 1.15

4 0

3 years ago

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Christine’s video store membership costs $5, and it costs $3.50 to rent a DVD. Christine spent $29.50 her first month. How many

dem82 [27]

Answer:

7 DVDs

Step-by-step explanation:

Christine spent $29.50 in total, and $5 on the membership.

so the amount of money spent on DVDs is $29.50 - $5, or $24.50.

The number of DVDs she rent are $24.50 / $3.50 = 7 DVDs

8 0

3 years ago

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(a) Plot the points (-5,4) and (7.8) in a rectangular coordinate system, (b) draw a line through the points, and (c) find and in

const2013 [10]

I think it should be (13,12) but I am not sure but it’s rise over run so that should be correct

6 0

3 years ago

Enter the correct answer in the box. Solve the quadratic equation by completing the square.

viktelen [127]

Answer:

Interpreting as: X=a-sqrt b X=a+sqrt b

Input:

X = a - sqrt(b) X = a + sqrt(b)

Alternate forms:

{a = (sqrt(b) + 1) X, a = X - sqrt(b), b = 0 ∨ X = -1}

{a = (sqrt(b) + 1) X, a + sqrt(b) = X, sqrt(b) (X + 1) = 0}

3 0

3 years ago

What is the center and radius of the circle defined by the equation (x-4)^2+(y-7)^2=49

AlekseyPX

Answers:

Center = (4, 7)

Radius = 7

===========================================================

Explanation:

The general template of any circle is

(x-h)^2 + (y-k)^2 = r^2

This general circle has these properties:

Center = (h,k)
Radius = r

Based on the equation your teacher gave you, we see that

h = 4
k = 7
r = 7, since 7^2 = 7*7 = 49

Therefore, this circle has center = (4,7) and radius = 7

Side note: The center's y coordinate and radius aren't always the same value.

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3 years ago

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