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Alexus [3.1K]
3 years ago
6

Find the distance between the points (3, -1) and (4, 6).

Mathematics
2 answers:
andrezito [222]3 years ago
6 0

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{3}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[4-3]^2+[6-(-1)]^2}\implies d=\sqrt{(4-3)^2+(6+1)^2} \\\\\\ d=\sqrt{50}\implies d\approx 7.07

Nuetrik [128]3 years ago
5 0

distance formula   so it is \sqrt[]{50}

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Step-by-step explanation:

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34kurt

Answer:

2⁵× 2ˣ = 256

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Step-by-step explanation:

2⁵× 2ˣ = 256

x= 3

use Product Rule: xᵃxᵇ=xᵃ⁺ᵇ

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2⁵⁺ˣ = 2⁸

cancel the base of 2 on both sides.

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subtract 5 from both sides.

x=8-5

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Answer:

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7)140°

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Step-by-step explanation:

1 = 40 °        <em>  [Vertically Opposite angles are equal]</em>

8 = 40 °         <em>[Corresponding Angles are equal]</em>

5 = 8 = 40°  <em> [Corresponding Angles are equal]</em>

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6 = 140°           <em> [Vertically Opposite angles are equal]</em>

2 = 140°            <em>[Corresponding Angles are equal]</em>

3 = 140 °          <em> [Vertically Opposite angles are equal]</em>

3 0
3 years ago
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