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bazaltina [42]
2 years ago
14

Find the length of AB

Mathematics
2 answers:
Paraphin [41]2 years ago
8 0

Answer:

52

Step-by-step explanation:

AB is the hypotenuse of the right triangle

sin34 = opp/hyp = 29/hyp

hyp = 29/sin34 = 51.860457849...

Sladkaya [172]2 years ago
5 0

Answer:

let \:  |ab|  \: be \: x \\  \\  \frac{ \sin(90) }{x}  =  \frac{ \sin(34) }{29}  \\ x \sin(34)  = 29 \sin(90)  \\ x =  \frac{29 \sin(90) }{ \sin(34) }  \\ x = 51.86(2.d.p) \\  |ab|  = 51.86

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7.37×10 with an exponent of nine
Harman [31]

Answer:

We get 6 x10^7 with a 4dp of 9599

 9599

  /     \

29    331

Step-by-step explanation:

Rounded to 4dp

64151584.9599

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt123" id="TexFormula1" title="\sqrt123" alt="\sqrt123" align="absmiddle" class="latex-fo
katrin [286]

Answer:

6.928588976577564467888

8 0
3 years ago
Sin(42) = cos(x) <br> Solve for x
mariarad [96]

Answer:

X = 48

Step-by-step explanation:

When you type sin(42) in your calculator it will give you something around 0.669.

If you try reverse sinus sin-1(0.669) it will give you 42.

Therefore you can say that:

Cos(x) = 0.669

So you can reverse the cos to get your answer

Cos-1(0.669) = 48

Or

Cos-1 (sin(42))

3 0
3 years ago
Find the perimeter of a rectangle whose length is 15 cm and length of one diagonal is 17cm
Ulleksa [173]

Answer:

<h2>46 cm</h2>

Step-by-step explanation:

first ,we use the Pythagorean theorem to determine the width:

width = √(17^2-15^2) = 8

then

perimeter = 2(width+lengt) = 2(8 + 15) = 2×23 = 46

6 0
3 years ago
Solve using Quadratic Formula <br>x^2 + 3x - 3 = 0​
katrin [286]

Answer:

a= 1 , b= 3 , c= –3

x =  \frac{ - b \frac{ + }{}  \sqrt{ {b}^{2}  - 4ac} }{2a}  \\ x =  \frac{ - 3  \frac{ + }{} {}  \sqrt{ {3}^{2}  - 4(1)( - 3)} }{2(1)}  \\  =   \frac{ - 3 \frac{ + }{}  \sqrt{9 + 12} }{2}  =  \frac{ - 3 \frac{ + }{} \sqrt{21}  }{2}  \\ \\  x =  \frac{ - 3 \frac{ + }{} \sqrt{21}  }{2}  \\  \\ x = 0.79 \\ x =  - 3.79

I hope I helped you^_^

4 0
3 years ago
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