Answer:
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<h2>
Answer with explanation:</h2>
Given : In a restaurant, the proportion of people who order coffee with their dinner is p.
Sample size : n= 144
x= 120

The null and the alternative hypotheses if you want to test if p is greater than or equal to 0.85 will be :-
Null hypothesis :
[ it takes equality (=, ≤, ≥) ]
Alternative hypothesis :
[its exactly opposite of null hypothesis]
∵Alternative hypothesis is left tailed, so the test is a left tailed test.
Test statistic : 

Using z-vale table ,
Critical value for 0.05 significance ( left-tailed test)=-1.645
Since the calculated value of test statistic is greater than the critical value , so we failed to reject the null hypothesis.
Conclusion : We have enough evidence to support the claim that p is greater than or equal to 0.85.
A' (3(-5),3(-4))= (-15,-12)
B' (3(2),3(6))=(6,18)
C'(3(4),3(-3))=(12,-9)
Equation 1 is
,
Equation 2 is [/tex] 3x-2y = -1 [/tex]
for first equation LCD= 3 *5 = 15 , So we multiply whole equation by 15


Now multiply second equation by -3 , to make the coefficient of y equal and opposite , so that we can apply the elimination method

Add both the equations


Divide both sides by 11

Plug in any one of the equation we get
3(3) -2y = -1
9 - 2y = -1
subtract 9 from both sides
-2y = -10
divide both sides by -2
y=5
So the solution is x= 3 , y= 5
Which means
a. The system is consistent and independent. TRUE