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Setler79 [48]
3 years ago
15

Titus wants to fence a square area of his yard for his dogs if you wants the area of the square to be a 121 square feet what doe

s the perimeter of the square need to be
Mathematics
2 answers:
Dmitrij [34]3 years ago
5 0

A square of area 121 ft² will have a side dimension of √121 ft = 11 ft. The perimeter is the length of 4 sides, so is 44 ft.

Ne4ueva [31]3 years ago
3 0

Answer: 44 feet.

Step-by-step explanation:

Let s be the side of square area .

Given : Titus wants to fence a square area of his yard for his dogs if you wants the area of the square to be a 121 square feet.

The area of square is given by :-

A=s^2

i.e. s^2=121

Taking square root on both sides, we get

s=11

The perimeter of square is given by :-

P=4s

i.e. P=4(11)=11\text{ feet}

Hence, the perimeter of the square need to be 44 feet.

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How do you do this question?
max2010maxim [7]

Answer:

∫₁⁵ 2t (t² + t³) dt

Step-by-step explanation:

The area is ∫ₓ₁ˣ² y dx.  To parameterize, replace x₁ and x₂ with t₁ and t₂.  Replace y = f(x) with y = f(t), and replace dx with (dx/dt) dt.

x = 5 + t², so dx = 2t dt.

∫₁⁵ (t² + t³) (2t dt)

∫₁⁵ 2t (t² + t³) dt

6 0
3 years ago
Sandra says that 90 divided by -9 equal 10. Is she correct ? Explain.
deff fn [24]

Answer:

-10

Step-by-step explanation:

In multiplying and dividing if there is 2 negatives it is always a positive but if it is 1 negative and a positive it is always a negative. This is only for multiplying and dividing. So the answer is negative 10.

6 0
3 years ago
Read 2 more answers
Pls do answer correct for brainliest
olga55 [171]

Answer:

3 \frac{1}{9}

6 0
3 years ago
Read 2 more answers
PLEASE HELP ME
anastassius [24]

the unscented candles burn faster at a rate of (1/3) inches/ hour

Step-by-step explanation:

scented candles:

(1/12) / (20/60) = 1/4 inches/ hour

unscented candles:

(1/6) / (30/ 60) = 1/3 inches/ hour

hope it helps!

4 0
2 years ago
A rectangle has its vertices at (-4, -3), (-4,7), (1,7), (1, -3). What part, in percent, of the rectangle is located in Quadrant
Rasek [7]

Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.

To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.

A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:

\overline{AB} = |A_y-B_y| = |-3-7| = |-10| = 10

Similarly, but exchanging the role of x and y, we compute the length of BC:

\overline{BC} = |B_x-C_x| = |-4-1| = |-5| = 5

So, the area of the rectangle is \overline{AB} \cdot \overline{BC} = 10\cdot 5 = 50

The same procedure allows us to compute width and height of the sub-rectangle in the third quadrant:

\overline{AE} = |A_y-E_y| = |-3-0| = |-3| = 3

\overline{EG} = |E_x-G_x| = |-4-0| = |-4| = 4

So, the area of the portion located in the third quadrant is \overline{AE} \cdot \overline{EG} = 3\cdot 4 = 12

This means that the ratio between the two area is

\cfrac{\text{area }AEGF}{\text{area }ABCD} = \cfrac{12}{50}

If we want this ratio to be a percentage, just make sure that the denominator is 100:

\cfrac{12}{50} = \cfrac{12}{50}\cdot \cfrac{2}{2} = \cfrac{24}{100} = 24\%

3 0
3 years ago
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