Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
Answer:
let me tell you firstly i am juat writing this
Step-by-step explanation:
for absolutely no rwason whatsoevwr lol
ao ywah get some hwlp from a pro
Answer:
Which statement best describes how to determine whether f(x) = 9 - 4x^2 is an odd function?
If n = the term number, then:
A(4) = 6-4(4-1)
A(4) = 6-4(3)
A(4) = 6-12
A(4) = -6
A = -1.5
Answer:
5,114.6
Step-by-step explanation:
5.1146 x 10^3 means move decimal point 3 to the right to get the answer
