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Studentka2010 [4]
2 years ago
8

Find the area of each trapezoid or kite

Mathematics
1 answer:
lara31 [8.8K]2 years ago
8 0

9514 1404 393

Answer:

  8)  42 in²

  9)  33 cm²

  10)  112 yd²

Step-by-step explanation:

8) The area is given by the formula ...

  A = 1/2(b1 +b2)h

  A = (1/2)(9 in +5 in)(6 in) = 42 in²

__

9) The area is half the product of the lengths of the diagonals.*

  A = 1/2(d1)(d2)

  A = 1/2(6 cm)(11 cm) = 33 cm²

__

10) As in the previous problem, ...

  A = 1/2(14 yd)(16 yd) = 112 yd²

_____

* This formula works for any quadrilateral with perpendicular diagonals.

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Reasoning If 1/2 of 1 is 1/2 what is 1/2 of 2,3 and 4
hichkok12 [17]

Answer:

half of 2 is 1, half of 3 is 1.5,half of 4 is 2.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
SOMEONE PLEASE HELPPP!!!
erastova [34]

Answer: 6 hours

Step-by-step explanation:

You would first start by making 1 3/5 into a mixed fraction. Getting 8/5. Then you’d divide that by 3/4 and get 6/5. Which then you’d multiply it by 5 and get 6 hours.

6 0
3 years ago
Which strategy should be used to correctly solve this problem?
hammer [34]
B, make a table of possible values

the best way to do it is actually not listed
to have max area with minimu perimiter, try to get the sides as close measure to each other as possible


I would pick B though

6 0
3 years ago
Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal
lisabon 2012 [21]

Given the following functions below,

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}

Factorising the denominators of both functions,

Factorising the denominator of f(x),

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}

Factorising the denominator of g(x),

\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}

Multiplying both functions,

undefined

4 0
1 year ago
Help me<br> Thanks if you answered
JulsSmile [24]

Answer:

number 21: 5 ten thousands, 7 hundreds, <em><u>7</u></em><em><u> </u></em>tens and 7 ones

Step-by-step explanation:

7 tens = 70

7 ones = 7

which equals 77, if the number is 50,777, you can see the last two digits in the tens and ones place are 7 and 7.

4 0
3 years ago
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