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irakobra [83]
3 years ago
13

P + nx=rx-e (solve for x)

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
8 0

Answer:

(p+e)/(r-n) =  x

Step-by-step explanation:

p + nx=rx-e

Add e to each side

p +e+ nx=rx-e+e

p +e+ nx=rx

Subtract nx from each side

p +e+ nx - nx=rx-nx

p+e = rx -nx

Factor out x

p+e = x(r-n)

Divide each side by (r-n)

(p+e)/(r-n) =  x(r-n)/(r-n)

(p+e)/(r-n) =  x

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Angle m AOC=108° m AOB=3x+4° m BOC=8x-28°<br><br> Find m AOB
Alex787 [66]

Hello from MrBillDoesMath!

Answer:

40



Discussion:

A diagram is always appreciated!

Assuming that

mAOC = mAOB    + mBOC       =>

108      = (3x + 4)  +  (8x - 28)    =>  combine common terms

108      = (3x + 8x) + (4 - 28 )     =>

108      = 11x - 24                        =>   add 24 to both sides

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x = 132/11 = 12


So mAOB = 3x + 4 = 3(12) + 4 = 36 + 4 = 40



Thank you,

MrB

4 0
3 years ago
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salantis [7]

Answer:

Below.

Step-by-step explanation:

One is (x - 3)^3.

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Alexxandr [17]
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hence, measure of the third side is 6x + 1

7 0
2 years ago
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