Answer:
The answer is:
12 ( y+ 
)
this suits perfectly the description
Answer:
h'(t)= -12
Step-by-step explanation:
h'(t)=d/dt (-6t x 2 + 24 + 6)
h'(t)=d/dt (-12t + 24 + 6)
h'(t)=d/dt (-12t + 30)
h'(t)=d/dt (-12t) + d/dt (30)
h'(t)= -12+0
Answer:
t(h)= (h-200)/-4.9
The time to reach a height of 50 meters is 30.6 seconds
Step-by-step explanation:
To express t as a function of height (h) we must transform the equation below:
h=200-4.9t
h-200=-4.9t
(h-200)/-4.9=t
t(h)= (h-200)/-4.9
To find the time to reach a height of 50 meters, we must replace this value on the new equation:
t(h)=50-200/-4.9
t(h)= 30.612
The time to reach a height of 50 meters is 30.6 seconds
25 - 7 = 18 |
18 - 3 = 15
The school received 15 kits in the box.
The reason why is because there are 3 kits that they haven't received yet. Then there were 7 that they already had, so that means there are 10 kits that wont be included in the box.
Sub (x+1) for x
f(x+1)=2(x+1)^2+3
f(x+1)=2(x^2+2x+1)+3
f(x+1)=2x^2+4x+2+3
f(x+1)=2x^2+4x+5
D is answer
