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Artist 52 [7]
3 years ago
6

If f(x) = 2x2 and g(x)= x2 + 2x, which expression represents f(g(x))?

Mathematics
1 answer:
andre [41]3 years ago
7 0

Answer:

f(g(x)) = 2(x^2 + 2x)^2

f(g(x)) = 2x^4 + 8x^3 + 8x^2

Step-by-step explanation:

Given;

f(x) = 2x^2

g(x) = x^2 + 2x

To derive the expression for f(g(x)), we will substitute x in f(x) with g(x).

f(g(x)) = 2(g(x))^2

f(g(x)) = 2(x^2 + 2x)^2

Expanding the equation;

f(g(x)) = 2(x^2 + 2x)(x^2 + 2x)

f(g(x)) = 2(x^4 + 2x^3 + 2x^3 + 4x^2)

f(g(x)) = 2(x^4 + 4x^3 + 4x^2)

f(g(x)) = 2x^4 + 8x^3 + 8x^2

Hope this helps...

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Answer:

8 cm and 10 cm

Step-by-step explanation:

Hello, <em> </em>I can help you with this.

Step 1

According to the question there are two rectangles A and B,

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in other words

Area_{A}=0.25*Area_{B} (Equation\ 1)\\

Step 2

Let

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Area_{A}=4\ cm * 5\ cm\\Area_{A}=20\ cm^{2}

put this value into equation 1

Area_{A}=0.25*Area_{B} (Equation\ 1)\\\\20\ cm^{2} =0.25*Area_{B} \\divide\ each\ side\ by\ 0.25\\\frac{20\ cm^{2} }{0.25}=\frac{0.25}{0.25}*Area_{B}\\  Area_{B}=80\ cm^{2}

Now, we know the area of rectangle B, to know its length we need to formule other equation

Step 3

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the ratio between the lengths must be constant, so the ratio of A must be equal to ratio in B, then

\frac{length(1A)}{length(2A)}=\frac{length(1B)}{length(2B)}  \\\\\\frac{4}{5}= \frac{length(1B)}{length(2B)}\\0.8=\frac{length(1B)}{length(2B)}\\length(1B)=0.8*length(2B) (Equation 3)

Step three

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put the value of length(1B) into equation (2)

length (1B)*length (2B)=80\ cm^{2} (equation\ 2)\\\(0.8*length(2B)) (*length (2B)=80\ cm^{2} \\\\0.8*(length (2B))^{2} =80\ cm^{2}\\(length (2B))^{2} =\frac{80\ cm^{2}}{0.8} \\(length (2B))^{2}=100\\\sqrt{(length (2B))^{2}}=\sqrt{100\ cm^{2}} \\ length (2B)=10\ cm

Now, put the value of length(2B) into equation 3 to know length (1B)

length(1B)=0.8*length(2B)\\length(1B)=0.8*10\ cm\\length(1B)=8 cm

I really hope this helps you, have a great day.

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