The equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1
Given a quadratic function for the transformations given the function f(x) = x²
If the function g(x) of the graph is translated 4 units to the left, the equation becomes (x-4)² (note that we subtracted 4 from the x value
- Translating the graph 1 unit up will give the final function g(x) as (x-4)² + 1 (We added 1 since it is an upward translation.)
Hence the equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1
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Answer:
is at a distance of 722 feet
Step-by-step explanation:
we have the angle that forms between the water and the imaginary line between the ship and the tip of the statue
we have the statue height that would be the opposite leg to our angle and we want to know the distance of the ship to the statue that would be the adjacent leg
we see that it has (angle, adjacent, opposite)
well to start we have to know the relationship between angles, legas and the hypotenuse
a: adjacent
o: opposite
h: hypotenuse
sin α = o/h
cos α= a/h
tan α = o/a
it's the tangent
tan α = o/a
we replace the values and solve
tan α = o/a
tan 22.9 = 305/a
a = 305/tan22.9
a = 305/0.4224
a = 722
is at a distance of 722 feet
6 2/3 i hope this helped you c:
4.56 - 3.2 equals 1.36. Hope this helps