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2 years ago

PLEASE HELP ASAP!!!!!

Mathematics

1 answer:

maw [93]2 years ago

3 0

Answer:

Step-by-step explanation

Since we are reflecting across the x axis, all of the y coordinates will remain the same. You find the distance away from the x = 4, double it, and add that value to x. So,

X' is now (8,3)

Y' is now (6,0)

Z' is now (4,2) because its x was 0, and anything * 0 = 0 so it does not move.

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A store is having a sale on jelly beans and trail mix. For 3 pounds of jelly beans and 2 pounds of trail mix, the total cost is

Nata [24]

the cost for each of jelly beans and each pound of trail mix is $2.5 and $1.75

<u>Step-by-step explanation:</u>

Given A store is having a sale on jelly beans and trail mix. For 3 pounds of jelly beans and 2 pounds of trail mix, the total cost is $11. For 5 pounds of jelly beans and 6 pounds of trail mix, the total cost is $23 . We have to find the cost for each pound of trail mix and each pound of jelly beans.

Let the cost of each pound of trail mix is $y.

and the cost of each pound of jelly beans is $x.

According to question,

For 3 pounds of jelly beans and 2 pounds of trail mix, the total cost is $11.

⇒ $3x+2y=11$ → (1)

For 5 pounds of jelly beans and 6 pounds of trail mix, the total cost is $23

⇒ $5x+6y=23$ → (2)

Solving (1) and (2), we get

3(1 equation)-(2 equation)=0

⇒ $3(3x+2y)-5x-6y=3(11)-23$

⇒ $9x+6y-5x-6y=10$

hence,

⇒ $4x=10$

⇒ $x=2.5$

Putting $x=2.5$ in $3x+2y=11$ we get ;

⇒ $3x+2y=11$

⇒ $3(2.5)+2y=11$

⇒ $2y=11-7.5=3.5$

⇒ $y=1.75$

Hence, the cost for each of jelly beans and each pound of trail mix is $2.5 and $1.75 .

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3 years ago

HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270

BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

$\large \boxed{sin \theta = tan \theta cos \theta} \\ \large \boxed{tan^{2} \theta + 1 = {sec}^{2} \theta}$

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

$\large{ {4}^{2} + 1 = {sec}^{2} \theta } \\ \large{16 + 1 = {sec}^{2} \theta } \\ \large{ {sec}^{2} \theta = 17}$

As we know, sec²θ = 1/cos²θ.

$\large \boxed{sec \theta = \frac{1}{cos \theta} } \\ \large \boxed{ {sec}^{2} \theta = \frac{1}{ {cos}^{2} \theta} }$

And thus,

$\large{ {cos}^{2} \theta = \frac{1}{17}} \\ \large{cos \theta = \frac{ \sqrt{1} }{ \sqrt{17} } } \\ \large{cos \theta = \frac{1}{ \sqrt{17} } \longrightarrow \frac{ \sqrt{17} }{17} }$

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

$\large{cos \theta = \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta = - \frac{ \sqrt{17} }{17}}$

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

$\large{sin \theta = 4 \times ( - \frac{ \sqrt{17} }{17}) } \\ \large{sin \theta = - \frac{4 \sqrt{17} }{17} }$

Answer

sinθ = -4sqrt(17)/17 or A choice.

4 0

2 years ago