Find an equation for the line that passes through the given point and satisfies the given conditions. 11) 11) p = ( 9 , 2 ); per
pendicular to v = 4 i + 4 j
1 answer:
You can use the direction vector as the coefficients of x and y for a line through (0, 0) perpendicular to that direction: x + y = 0. (A common factor of 4 can be removed from the coefficients.)
Translating the line up 2 and right 9, so it goes through the given point, we get ...
... (x -9) +(y -2) = 0
or
... x + y = 11
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