Find an equation for the line that passes through the given point and satisfies the given conditions. 11) 11) p = ( 9 , 2 ); per
pendicular to v = 4 i + 4 j
1 answer:
You can use the direction vector as the coefficients of x and y for a line through (0, 0) perpendicular to that direction: x + y = 0. (A common factor of 4 can be removed from the coefficients.)
Translating the line up 2 and right 9, so it goes through the given point, we get ...
... (x -9) +(y -2) = 0
or
... x + y = 11
You might be interested in
There are two intersection points (-1, 1) and (-2, 3), and the x coordinates are -1 and -2.
<h3>What is an exponential function?</h3>It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent y = a^x
where a is a constant and a>1
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have two equations:
y = –2x – 1 and
From the graph, we can see:
There are two intersection points:
(-1, 1) and (-2, 3)
The x coordinates are -1 and -2
x = -1, y = 1
x = -2, y = 3
Thus, there are two intersection points (-1, 1) and (-2, 3), and the x coordinates are -1 and -2.
Learn more about the exponential function here:
#SPJ1
