Answer:
f=3x-2
Step-by-step explanation:
Answer:
The value of the acount after t years is of
The annual growth rate is of 0.72%.
Step-by-step explanation:
Compound interest:
The compound interest formula is given by:
Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.
$650 is invested in an account earning 8.6% interest (APR), compounded monthly.
This means that . So
The value of the acount after t years is of
Annual growth rate
1.0072 - 1 = 0.0072 = 0.72%
The annual growth rate is of 0.72%.
Answer:
for this type of question, integral by parts should be used . This involves using the formula for intregation by parts:
intudv=uv-intvdu.
lets first break apart the x and e10x into two parts - "u" and "v"
where u = x.
however, we need to find the value of v. in order to do this, we can integrate dv/dx in order to get to v.
the value of dv/dx is : e10x
u = x dv/dx = e10x
as seen in the formula, you need to have a value for u, dv, v and du.
therefore in order to get du you must differentiate u:
u = x
du/dx = 1
du = 1dx = dx
du = dx
in order to get v you need to integrate dv/dx:
\displaystyle \inte10x dx = 1/10 x10x
now that we have both parts, we can put this back into the formula.
intudv=uv-intvdu.
\displaystyle \intxe10x = x * 1/10e10x - \displaystyle \int1/10e10x dx
Step-by-step explanation:
There are 16 ounces in 1 pound.
The students spend 1274 hours in school.
<h3>How to determine the number</h3>
From the information given, we have that:
- There are 182 school days
- Each school days take 7 hours
We can then say that, if takes 7 hours for each school day and there are 182 days, then the hours students spent in school is;
= 182 days × 7 hours
Multiply through
= 1274 hours
The students are in school for 1274 hours.
Hence, the students spend 1274 hours in school.
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