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sweet [91]
3 years ago
15

How do you solve #21?

Mathematics
1 answer:
Inessa05 [86]3 years ago
6 0
5x^3+8x^2/3x^4-16x^2=x^2(5x+8)/x^2(3x^2-16)=5x+8/3x^2-16
lim x--->0 5x+8/3x^2-16=8/-16=-1/2
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Please help? i’m not good with math at all- <br> ^^<br> that’s embarrassing
Nata [24]

Answer:

The answer is A. If not then I'm sorry ☹

6 0
3 years ago
F(x)=x^4+3, g(x)=x-7 and h(x)=square root of x then f(g(h(x))=
SpyIntel [72]

Answer:

<em>x² - 28x√x + 294x - 1372√x + 2404 </em>

Step-by-step explanation:

f(x) = x^{4} + 3

g(x) = x - 7

h(x) = √x

f(g(h(x))) - ?

g(h(x)) = √x - 7

f(g(h(x))) = (\sqrt{x} -7) ^{4} + 3 = ( √x - 7 )² × ( √x - 7 )² + 3 =

= (x - 14√x + 49)(x - 14√x + 49) + 3 =

= x² - 14x√x + 49x - 14x√x + 196x - 686√x + 49x - 686√x + 2401 + 3 =

=  <em>x² - 28x√x + 294x - 1372√x + 2404</em>

8 0
2 years ago
What is the solution to the inequality shown below?
lesantik [10]

To solve the inequality, you need to isolate/get the variable "p" by itself in the inequality:

5p + 26 < 72           Subtract 26 on both sides

5p + 26 - 26 < 72 - 26

5p < 46      Divide 5 on both sides to get "p" by itself

\frac{5p}{5}

p

p < 9.2       Your answer is A

8 0
3 years ago
Are these lines parallel perpendicular or neither
Natasha_Volkova [10]

Answer:

perpendicular

Step-by-step explanation:

start but putting each line into the standard line format

2x-y=-5

-y=-2x-5

y=2x+5

x+2y=-6

2y=-x-6

y=-(1/2)x-3

if lines are parallel the slopes would be the same. 2 is not equal to -1/2

if lines are perpendicular the slope of one would be the opposite inverse of the other.

negative inverse of 2 = - (1/2)

so the lines are perpendicular

8 0
3 years ago
Help plz aidjkeksnszhosksoaoaoaozizbzbzjsijssj
mojhsa [17]
The answer is c because the number of tickets (t) times the number of adults is the total cost
6 0
2 years ago
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