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sweet [91]
3 years ago
15

How do you solve #21?

Mathematics
1 answer:
Inessa05 [86]3 years ago
6 0
5x^3+8x^2/3x^4-16x^2=x^2(5x+8)/x^2(3x^2-16)=5x+8/3x^2-16
lim x--->0 5x+8/3x^2-16=8/-16=-1/2
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which of the following best describe the blue line in the image below A. The line constructed through point P that is parallel t
lesya692 [45]

Answer:

Option B.

Step-by-step explanation:

Option A. "The line constructed through point P that is parallel to line B."

     Since parallel lines never intersect each other, a line intersecting line AB at point P will not be parallel.

Therefore, Option (A) is incorrect.

Option (B). "The line constructed through point P that is perpendicular to line AB."

    Since the angle between line AB and a line constructed through point P has been given as 90°, line through point P will be perpendicular to AB.

Therefore, Option (B) is the answer.

Option C. "The line constructed through point P that intersects line AB at two different points."

    Since, two perpendicular lines intersect each other at only one point, the line constructed from point P will not intersect line AB at two different points.

Therefore, Option C is not correct.

8 0
3 years ago
A car travels 10 km southeast and then 15 km in a direction 60° north of east. Find the magnitude of the car's resultant vector.
ra1l [238]

Answer:

60×10 =600<u>÷</u><u>1</u><u>5</u><u>=</u><u>4</u><u>0</u>

Step-by-step explanation:

oh that's my answer

5 0
2 years ago
Read 2 more answers
A 1400 kg car moving +13.7 m/s makes an elastic collision with a 3200 kg truck, initially at rest. What is the velocity of the c
Kamila [148]

Answer:

The velocity of the car after the collision is -5.36 m/s

Step-by-step explanation:

An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.

let the following:

m₁ = mass of the car = 1400 kg

m₂ = mass of the truck = 3200 kg

u₁ = velocity of the car before collision = 13.7 m/s

u₂ = velocity of the truck before collision = 0 m/s

v₁ = velocity of the car after collision

v₂ = velocity of the truck after collision

v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)

   =  [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)

   = - 5.36 m/s

So, <u>the velocity of the car after the collision is -5.36 m/s</u>

7 0
3 years ago
62.5% as a decimal <br>please help me
tamaranim1 [39]
0.625 is the answer hope that hepled
5 0
3 years ago
Read 2 more answers
How do you solve -3x-4&gt;5
Salsk061 [2.6K]

Answer: x < -3

Step-by-step explanation:

-3*x-4-(5)>0

7 0
3 years ago
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