<img src="https://tex.z-dn.net/?f=%5Chuge%7B%5Cgray%7B%5Csf%20Question%3A%7D%20%7D" id="TexFormula1" title="\huge{\gray{\sf Ques

Ask question

Ask question

All categories

andrew-mc [135]

3 years ago

9

tion:} }" alt="\huge{\gray{\sf Question:} }" align="absmiddle" class="latex-formula">
A body describes simple harmonic motion with an amplitude of 5 cm and a period of 0.2 s. Find the acceleration and velocity of the body when the displacement is (a) 5 cm, (b) 3 cm and (c) 0 cm.

1 answer:

charle [14.2K]3 years ago

3 0

Answer:

ANSWER

A = 5 cm = 0.05 m

T = 0.2 s

ω=2π/T=2π/0.2=10πrad/s

plz give brainlist

hope this helped

You might be interested in

onsider the free body diagram. If the sum of the tension forces is equal to the force of gravity, which description BEST applies

cluponka [151]

The answer is C) A girl hangs by both hands, motionless, from a trapeze.

5 0

2 years ago

When a space shuttle takes off, the chemical reactions of the fuel give the shuttle the kinetic energy to leave Earth's atmosphe

inessss [21]

Answer:a

Explanation:

Because its has to use tihs potential energy to overcome the atmosphere so the shuttle will not go back down

6 0

2 years ago

At a particular instant, a proton at the origin has velocity < 5e4, -2e4, 0> m/s. You need to calculate the magnetic field

vesna_86 [32]

Answer:

$9.7\times 10^{-5} T$

Explanation:

Velocity = $5\times 10^4i-2\times 10^4j$

r= $0.03i+0.05j$

r= $\mid r\mid=\sqrt{(0.03)^2+(0.05)^2}=0.058$

v= $\mid V\mid=\sqrt{(5\times 10^4)^2+(-2\times 10^{4})^2}=5.39\times 10^{2}$

We know that

$B=\frac{mv}{qr}$

Where q= $1.6\times 10^{-19} C$

Mass of proton= $1.67\times 10^{-27} kg$

Using the formula

$B=\frac{1.67\times 10^{-27}\times 5.39\times 10^2}{1.6\times 10^{-19}\times 0.058}$

$B=9.7\times 10^{-5} T$

3 0

3 years ago

Ivan

Answer:

car B will be 30 Km ahead of car A.

Explanation:

We'll begin by calculating the distance travelled by each car. This is illustrated below:

For car A:

Speed = 40 km/h

Time = 3 hours

Distance =?

Speed = distance / time

40 = distance / 3

Cross multiply

Distance = 40 × 3

Distance = 120 Km

For car B:

Speed = 50 km/h

Time = 3 hours

Distance =?

Speed = distance / time

50 = distance / 3

Cross multiply

Distance = 50 × 3

Distance = 150 Km

Finally, we shall determine the distance between car B an car A. This can be obtained as follow:

Distance travelled by car B (D₆) = 150 Km

Distance travelled by car A (Dₐ) = 120 Km

Distance apart =?

Distance apart = D₆ – Dₐ

Distance apart = 150 – 120

Distance apart = 30 Km

Therefore, car B will be 30 Km ahead of car A.

7 0

3 years ago

A guitar vibrates in frequency with a tuning fork when the fork is held against its body. This is a case of

Butoxors [25]

Energy transfer the energy from the tuning fork is being transferred to the guitar<span />

4 0

3 years ago