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3 years ago

A correlation coefficient represents what two things

Physics

1 answer:

kenny6666 [7]3 years ago

3 0

Answer:

A correlation coefficient represents the following:

1- The direction of the relationship

2- The strength of the relationship

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What rule does static electricity follow

Luba_88 [7]

Static electricity works when there is an imbalance of positive and negative charges, and thus causes a little spark.

3 0

3 years ago

A current of 1.8 A delivers 2.5 C of charge. How much time was required? 0.70 s 0.72 s 1.4 s 4.5 s

Natalka [10]

Answer:

1.4 s

Explanation:

Given the following data;

Quantity of charge, Q = 2.5 C

Current = 1.8 A

To find the time required;

Mathematically, the quantity of charge passing through a conductor is given by the formula;

Quantity of charge, Q = current * time

Substituting into the formula, we have;

2.5 = 1.8 * time

Time = 2.5/1.8

Time = 1.4 s

5 0

3 years ago

Read 2 more answers

Una fuerza F de 200 lb actúa a lo largo de AB, sobre la rampa mostrada. fuerza de F respecto del eje OC. Calcule el momento de f

ruslelena [56]

Answer:

Moc = -613.25 [lb*in]

Explanation:

Este problema se puede resolver mediante la mecánica vectorial, es decir se realizara un analisis de vectores.

Primero se calculara el momento de la fuerza F_AB con respecto al punto O, debemos recordar que el momento con respecto a un punto se define como el producto cruz de la distancia por la fuerza.

$M_{o}=r_{A/O} * F_{AB}$ (producto cruz)

Necesitamos identificar los puntos:

O (0,0,0) [in]

A (12,0,0) [in]

B (0, 24,8) [in]

C (12,24,0) [in]

$r_{A/O}=(12,0,0) - (0,0,0)\\r_{A/O} = 12 i + 0j+0k [in]\\AB = (0,24,8) - (12,0,0)\\AB = -12i+24j+8k [in]\\[LAB]=\frac{-12i+24j+8k}{\sqrt{(12)^{2} +(24)^{2} +(8)^{2} } }\\ LAB=-\frac{3}{7} i+\frac{6}{7}j+\frac{2}{7}k$

El ultimo vector calculado corresponde al vector unitario (magnitud = 1) de AB. El vector fuerza corresponderá al producto del vector unitario por la magnitud de la fuerza = 200 [lb].

$F_{AB}=-\frac{600}{7} i +\frac{1200}{7}j+\frac{400}{7} k [Lb]$

De esta manera realizando el producto cruz tenemos

$M_{O}=r_{A/O} * F_{AB}$

$M_{O}=0i-685.7j+2057.1k [Lb*in]$

Para calcular el momento con respecto a la diagonal OC, necesitamos el vector unitario de esta diagonal.

$OC = (12,24,0)-(0,0,0)\\OC= 12i+24j+0k[Lb]\\LOC = \frac{12i+24j+0k}{\sqrt{(12)^{2} +(24)^{2} +(0)^{2} } } \\LOC=\frac{12}{\sqrt{720}}i+\frac{24}{\sqrt{720}}j +0k$

El vector con respecto al eje OC, es igual al producto punto del momento en el punto O por el vector unitario LOC

$M_{OC}=L_{OC}*M_{O}\\M_{OC}=(\frac{12}{\sqrt{720}}i +\frac{24}{\sqrt{720}} j+0k )* (0i-685.7j+2057.1k)\\M_{OC}= -613.32[Lb*in]$

7 0

3 years ago

Tarzan is running with a horizontal velocity, along level ground. While running, he encounters a 2.21 m vine of negligible mass,

Lena [83]

Answer:

a) $a_c = 1.09m/s^2$

b) T = 720.85N

Explanation:

With a balance of energy from the lowest point to its maximum height:

$m*g*L(1-cos\theta)-1/2*m*V_o^2=0$

Solving for $V_o^2$ :

$V_o^2=2*g*L*(1-cos\theta)$

$V_o^2=2.408$

Centripetal acceleration is:

$a_c = V_o^2/L$

$a_c = 2.408/2.21$

$a_c = 1.09m/s^2$

To calculate the tension of the rope, we make a sum of forces:

$T - m*g = m*a_c$

Solving for T:

$T =m*(g+a_c)$

T = 720.85N

3 0

4 years ago

Samburu the elephant has a mass of 1650kg. If each of his feet cover an area of .25 m^2, how much pressure does samburu exert on

lidiya [134]

Samburu's weight is (mass x gravity) = (1650kg x 9.8 m/s²) = 16,170 Newtons.

Samburu's contact area with the ground is (0.25 m²/hoof) x (4 hoofs) = 1 m² .

Pressure = (force) / (area) = (16,170 Newtons) / (1 m²) = 16,170 Pascal .

8 0

3 years ago