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3 years ago

A correlation coefficient represents what two things

Physics

1 answer:

kenny6666 [7]3 years ago

3 0

Answer:

A correlation coefficient represents the following:

1- The direction of the relationship

2- The strength of the relationship

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Answer:

Rita and Katrina both followed similar paths into the Gulf.

Explanation:

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3 years ago

The force that acts on an object lying on a surface, acting in a direction perpendicular to the surface is called ____________

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2 years ago

German physicist Werner Heisenberg related the uncertainty of an object's position ( Δ x ) to the uncertainty in its velocity (

timama [110]

According to the information given, the Heisenberg uncertainty principle would be given by the relationship

$\Delta x \Delta v \geq \frac{h}{4\pi m}$

Here,

h = Planck's constant

$\Delta v$ = Uncertainty in velocity of object

$\Delta x$ = Uncertainty in position of object

m = Mass of object

Rearranging to find the position

$\Delta x \geq \frac{h}{4\pi m\Delta v}$

Replacing with our values we have,

$\Delta x \geq \frac{6.625*10^{-34}m^2\cdot kg/s}{4\pi (9.1*10^{-31}kg)(0.01*10^6m/s)}$

$\Delta x \geq 5.79*10^{-9}m$

Therefore the uncertainty in position of electron is $5.79*10^{-9}m$

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3 years ago

The driver of a car slams on the brakes, causing the car to slow down at a rate of 17ft/s2 as the car skids 285ft to a stop.

ozzi

1) 5.79 s

2) 98.4 ft/s

Explanation:

The motion of the car is a uniformly accelerated motion (it means it travels with constant acceleration), so we can find the time it takes for the car to stop by using the following suvat equation:

$s=vt-\frac{1}{2}at^2$

where

s is the distance travelled

v is the final velocity

t is the time

a is the acceleration of the car

In this problem we have:

s = 285 ft is the distance travelled

$a=-17 ft/s^2$ is the acceleration of the car (negative since the car is slowing down)

v = 0 ft/s is the final velocity of the car, since it comes to a stop

Solving for t, we find:

$t=\sqrt{\frac{-2s}{a}}=\sqrt{\frac{-2(285)}{-17}}=5.79 s$

The initial speed of the car can be found by using another suvat equation, namely:

$v=u+at$

where

v is the final speed

u is the initial speed

a is the acceleration

t is the time

In this problem, we have:

v = 0 is the final speed of the car

$a=-17 ft/s^2$ is the acceleration of the car (negative since the car is slowing down)

t = 5.79 s is the total time of motion (found in part 1)

Therefore, the initial speed of the car is:

$u=v-at=0-(-17)(5.79)=98.4 ft/s$

8 0

3 years ago