0.7777777778
there you go your welcome
Answer:
b = 
Step-by-step explanation:
Given
k = 
← multiply both sides by (v - b)
k(v - b) = brt ← distribute left side
kv - kb = brt ( subtract brt from both sides )
kv - kb - brt = 0 ( subtract kv from both sides )
- kb - brt = - kv ( multiply through by - 1 to clear the negatives )
kb + brt = kv ← factor out b from each term on the left
b(k + rt ) = kv ← divide both sides by (k + rt )
b =
Answer:
a) 0.857
b) 0.571
c) 1
Step-by-step explanation:
Based on the data given, we have
- 18 juniors
- 10 seniors
- 6 female seniors
- 10-6 = 4 male seniors
- 12 junior males
- 18-12 = 6 junior female
- 6+6 = 12 female
- 4+12 = 16 male
- A total of 28 students
The probability of each union of events is obtained by summing the probabilities of the separated events and substracting the intersection. I will abbreviate female by F, junior by J, male by M, senior by S. We have
- P(J U F) = P(J) + P(F) - P(JF) = 18/28+12/28-6/28 = 24/28 = 0.857
- P(S U F) = P(S) + P(F) - P(SF) = 10/28 + 12/28 - 6/28 = 16/28 = 0.571
- P(J U S) = P(J) + P(S) - P(JS) = 18/28 + 10/28 - 0 = 1
Note that a student cant be Junior and Senior at the same time, so the probability of the combined event is 0. The probability of the union is 1 because every student is either Junior or Senior.
10-8=2 you cant take 8 from 2 so there your answer......2
F(3)=-4(3)+3=-9
g(3)=3(3)+4=13
f(3).g(3)=-9*13=-117
