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3 years ago

Find the exact value of sin (pi/3 + pi)

Mathematics

2 answers:

Nadya [2.5K]3 years ago

6 0

Answer:umm I think to do that you need to สะเดมแคพสพว เุ่ะมำงกรด พรพเ่พยวพ

Step-by-step explanation:ระะทืะยะะืะนะทะ ถระทพนดทเรทเสเยเสเรเาดยเสะมะนเสเร้าเสพ

finlep [7]3 years ago

6 0

I believe the the answer is the square root of 32

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A restaurant receives a shipment of

natka813 [3]

Subtract the amount used from the total packets:

5000 - 1824 = 3176 left after the first week.

3176 - 2352 = 824 total packets left.

7 0

3 years ago

(Photo attached) Trig question. I partially understand it, but not completely. Please explain! :) Thanks in advance.

aliya0001 [1]

Answer:

A = 2
B = 3

Step-by-step explanation:

You can start by recognizing 19/12π = π +7/12π, so the desired sine is ...

sin(19/12π) = -sin(7/12π) = -(sin(3/12π +4/12π)) = -sin(π/4 +π/3)

-sin(π/4 +π/3) = -sin(π/4)cos(π/3) -cos(π/4)sin(π/3)

Of course, you know that ...

sin(π/4) = cos(π/4) = (√2)/2

cos(π/3) = 1/2

sin(π/3) = (√3)/2

So, the desired value is ...

sin(19π/12) = -(√2)/2×1/2 -(√2)/2×(√3/2) = -(√2)/4×(1 +√3)

Comparing this form to the desired answer form, we see ...

A = 2

B = 3

5 0

3 years ago

What is 3:120 equivalent to

fenix001 [56]

1:40 because if we think of this just like a fraction $\frac{3}{120}$ that simplifys down to $\frac{1}{40}$ and because fraction simplifications are similar (related to each other) we can concur that these would be too.

Enjoy!=)

6 0

3 years ago

Read 2 more answers

Find two positive consecutive odd integers such that square of the smaller integer is 10 more than the larger integer

Otrada [13]

Let $2n+1$ be the smaller integer. The larger integer is then $2n+3$ , and we have

$(2n+1)^2=10+(2n+3)\implies4n^2+4n+1=2n+13$

$\implies4n^2+2n-12=0$

$\implies2n^2+n-6=0$

$\implies(2n-3)(n+2)=0$

$\implies 2n-3=0\text{ or }n+2=0$

$\implies n=\dfrac32\text{ or }n=-2$

We omit $n=-2$ , since $2(-2)+1=-3$ is negative.

Then for $n=\dfrac32$ we find $2\left(\dfrac32\right)+1=4$ , but this is not odd.

There are no consecutive odd integers that satisfy the given condition!

3 0

3 years ago

A plane flying horizontally at an altitude of 1 mi and a speed of 470 mi/h passes directly over a radar station. Find the rate a

kiruha [24]

Answer:

407 mi/h

Step-by-step explanation:

Given:

Speed of plane (s) = 470 mi/h

Height of plane above radar station (h) = 1 mi

Let the distance of plane from station be 'D' at any time 't' and let 'x' be the horizontal distance traveled in time 't' by the plane.

Consider a right angled triangle representing the above scenario.

We can see that, the height 'h' remains fixed as the plane is flying horizontally.

Speed of the plane is nothing but the rate of change of horizontal distance of plane. So, $s=\frac{dx}{dt}=470\ mi/h$

Now, applying Pythagoras theorem to the triangle, we have:

$D^2=h^2+x^2\\\\D^2=1+x^2$

Differentiating with respect to time 't', we get:

$2D\frac{dD}{dt}=0+2x\frac{dx}{dt}\\\\\frac{dD}{dt}=\frac{x}{D}(s)$

Now, when the plane is 2 miles away from radar station, then D = 2 mi

Also, the horizontal distance traveled can be calculated using the value of 'D' in equation (1). This gives,

$2^2=1+x^2\\\\x^2=4-1\\\\x=\sqrt3=1.732\ mi$

Now, plug in all the given values and solve for $\frac{dD}{dt}$ . This gives,

$\frac{dD}{dt}=\frac{1.732\times 470}{2}=407.02\approx 407\ mi/h$

Therefore, the distance from the plane to the station is increasing at a rate of 407 mi/h.

6 0

3 years ago