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Contact [7]
3 years ago
11

In a load of 3/4 ton of steel rods, 1/8 of them are bent. how many tons of steel rods are bent?

Mathematics
1 answer:
Verdich [7]3 years ago
8 0
6/8 steel Roda are bent
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If you want to place 9 3/4 inch towel bar in the center of a door that is 27 1/2 wide, how much space will be on each side of th
marysya [2.9K]
The answer is 11 \frac{5}{6} inches

Step 1. Subtract length of the door from the width of the door:
27 \frac{1}{2} - 9 \frac{3}{4} =  \frac{55}{2} - \frac{39}{4} =\frac{110}{4} - \frac{39}{4}= \frac{71}{4}

Step 2. You want the same space to be on each side of the bar. So, divide the difference from step 1 by 2:
\frac{71}{4} : 2 = \frac{71}{4} :  \frac{2}{1} =\frac{71}{4} * \frac{1}{2}= \frac{71}{6} =  \frac{66+5}{6}= \frac{66}{6}+ \frac{5}{6}=11 \frac{5}{6}
3 0
3 years ago
Read 2 more answers
5.
Delicious77 [7]

You can solve for the velocity and position functions by integrating using the fundamental theorem of calculus:

<em>a(t)</em> = 40 ft/s²

<em>v(t)</em> = <em>v </em>(0) + ∫₀ᵗ <em>a(u)</em> d<em>u</em>

<em>v(t)</em> = -20 ft/s + ∫₀ᵗ (40 ft/s²) d<em>u</em>

<em>v(t)</em> = -20 ft/s + (40 ft/s²) <em>t</em>

<em />

<em>s(t)</em> = <em>s </em>(0) + ∫₀ᵗ <em>v(u)</em> d<em>u</em>

<em>s(t)</em> = 10 ft + ∫₀ᵗ (-20 ft/s + (40 ft/s²) <em>u</em> ) d<em>u</em>

<em>s(t)</em> = 10 ft + (-20 ft/s) <em>t</em> + 1/2 (40 ft/s²) <em>t</em> ²

<em>s(t)</em> = 10 ft - (20 ft/s) <em>t</em> + (20 ft/s²) <em>t</em> ²

6 0
2 years ago
The stock's value dropped from $38.50 to $34.00.What negative number shows the change in value?
schepotkina [342]
$-4.50 change in value
5 0
3 years ago
What is the simplified from of pi √3-8 pi√3<br>​
irina [24]

Answer:

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Step-by-step explanation:

Treating pi as a variable, the simplified value can be written as;

-7pi √3

This can be obtained from using the following simple methodology;

pi(√3 -8 √3)

= pi (-7 √3)

6 0
3 years ago
I need help with only one question on number 4? anyone pls?
Murljashka [212]
I think 2,-2 is right
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2 years ago
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