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Contact [7]
3 years ago
11

In a load of 3/4 ton of steel rods, 1/8 of them are bent. how many tons of steel rods are bent?

Mathematics
1 answer:
Verdich [7]3 years ago
8 0
6/8 steel Roda are bent
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​it's believed that as many as 2222​% of adults over 50 never graduated from high school. we wish to see if this percentage is t
jenyasd209 [6]

The given values are:

p =  22% = 0.22

Zc = 1.645 at 90% confidence level.

margin of error, E = 0.04

 

The formula we can use here is:

E = sqrt(pq/n) * Zc

 0.04 = sqrt(0.22*(1-0.22)/n)*1.645

n = (0.22*(1-0.22))*(1.645/0.04)^2

n = 290.22

 

hence minimum sample size = 290 

7 0
3 years ago
Help me with this math work please
Aloiza [94]
Your photo is super blurry! I can’t read parts of the problems, so I can’t exactly help you. Sorry! Good luck.
7 0
2 years ago
Read 2 more answers
What is the common ratio of the geometric sequence: -1/12, -1/2,-3,-18...?
makvit [3.9K]
The answer is B 1/6 just divide the first number by the second one<span />
4 0
3 years ago
Question:
prohojiy [21]

Answer:

x = 3/2 + sqrt(17)/2 or x = 3/2 - sqrt(17)/2

Step-by-step explanation:

Solve for x over the real numbers:

x/x - 1 = x - 3 - 2/x

x/x - 1 = 0:

0 = x - 3 - 2/x

0 = x - 3 - 2/x is equivalent to x - 3 - 2/x = 0:

x - 3 - 2/x = 0

Bring x - 3 - 2/x together using the common denominator x:

(x^2 - 3 x - 2)/x = 0

Multiply both sides by x:

x^2 - 3 x - 2 = 0

Add 2 to both sides:

x^2 - 3 x = 2

Add 9/4 to both sides:

x^2 - 3 x + 9/4 = 17/4

Write the left hand side as a square:

(x - 3/2)^2 = 17/4

Take the square root of both sides:

x - 3/2 = sqrt(17)/2 or x - 3/2 = -sqrt(17)/2

Add 3/2 to both sides:

x = 3/2 + sqrt(17)/2 or x - 3/2 = -sqrt(17)/2

Add 3/2 to both sides:

Answer: x = 3/2 + sqrt(17)/2 or x = 3/2 - sqrt(17)/2

3 0
3 years ago
The asymptote function f(x)=3^x+4 is y=
swat32

The asymptote of the function f(x)=3^x is y = 0.

The asymptote of the function f(x)=3^x+4 is y = 0+4=4

Answer: y = 4

7 0
3 years ago
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