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Viktor [21]
3 years ago
7

Evaluate the expression when a=−2, b=3, and c=−8. −ab3−ac=?

Mathematics
2 answers:
Rina8888 [55]3 years ago
7 0

the anwser would be -2 because -2*3*3-2*8 equals -2

Lana71 [14]3 years ago
3 0

Answer:

The value of the expression when a=−2, b=3, and c=−8 is 38.

Step-by-step explanation:

Consider the provided expression.

-ab^3-ac

We need to solve the expression when a=−2, b=3, and c=−8.

Substitute the respective values in the provided expression.

-(-2)(3)^3-(-2)(-8)

Simplify the expression.

(2)(27)-(2)(8)

54-16

38

Hence, the value of the expression when a=−2, b=3, and c=−8 is 38.

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4 0
2 years ago
One of the roots of the equation x2−5x+q=0 is 2. Find the other root and the value of the coefficient q.
pishuonlain [190]

Answer:

q=6

Step-by-step explanation:

A root can be plugged in for X, so 2(2)-5(2)+q=0. This means -6+q=0. We can now even them out and know q=6

8 0
3 years ago
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What is the measure?
Ivanshal [37]
The answer for this problem: Option C.
5 0
3 years ago
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Solve equation by using the quadratic formula.
Sati [7]

Answer: 1:  x=3, x=1

2:  x= -5

3:  There are 2 real solutions.

4:  There are 2 real solutions.

5:  There are no real solutions.

6.  There is 1 real solution.

7.  

8.  x= -6, x = -2

9.  x = -1/6, x=1

10.  

Explanation:

1.  The quadratic formula is

Substituting our known information we have:

2.  Rewriting the quadratic in standard form we have x²+10x-25=0. Substituting this into the quadratic formula gives us:

3.  The discriminant is b²-4ac.  For this problem, that is 20²-4(-4)(25)=400--400=800.  Since this is greater than 0, there are 2 real solutions.

4.  The discriminant in this problem is 7²-4(2)(-15)=49--120=49+120=169.  This is greater than 0, so there are 2 real solutions.

5.  The discriminant in this problem is 1²-4(-2)(-28)=1-224=-223.  Since this is less than 0, there are no real solutions.

6.  If the discriminant of a quadratic is 0, then by definition there is 1 real solution.

7.  Rewriting the quadratic we have 3x²-4x-2=0.  Using the quadratic formula we have:

8.  Factoring this trinomial we want factors of 12 that sum to 8.  6*2 = 12 and 6+2=8, so those are our factors.  This gives us:

(x+6)(x+2)=0

Using the zero product property we know that either x+6=0 or x+2=0.  Solving these equations we get x= -6 or x= -2.

9.  Factoring this trinomial we want factors of 6(-1)=-6 that sum to -5.  (-6)(1)=-6 and -6+1=-5, so this is how we "split up" the x term:

6x²-6x+1x-1=0

We group together the first two and the last two terms:

(6x²-6x)+(1x-1)=0

Factor the GCF out of each group.  In the first group, that is 6x:

6x(x-1)+(1x-1)=0

In the second group, the GCF is 1:

6x(x-1)+1(x-1)=0

Both terms have a factor of (x-1), so we can factor it out:

(x-1)(6x+1)=0

Using the zero product property, we know either x-1=0 or 6x+1=0.  Solving these equations we get x=1 or x=-1/6.

10.  Substituting our information into the quadratic formula we get:

Step-by-step explanation:

5 0
2 years ago
(T+10.5) + 2t + 90 = 180
Masja [62]

Answer:

x = 26.5

Step-by-step explanation:

Step 1: Write equation

(t + 10.5) + 2t + 90 = 180

Step 2: Solve for <em>t</em>

<u>Combine like terms:</u> 3t + 100.5 = 180

<u>Subtract 100.5 on both sides:</u> 3t = 79.5

<u>Divide both sides by 3:</u> t = 26.5

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

<u>Substitute:</u> (26.5 + 10.5) + 2(26.5) + 90 = 180

<u>Parenthesis:</u> 37 + 56 + 90 = 180

<u>Add:</u> 180 = 180

∴ x = 26.5

5 0
3 years ago
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