Question

Find an equation for the line that passes through the points (-1,2) and (5,5)

Answer 1

Answer:

-The equation for the problem:

$y = \frac{1}{2}x + \frac{5}{2}$

Step-by-step explanation:

-First, you need determine the slope of a line:

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ (where $(x_{1},y_{1})$ is the first coordinate and $(x_{2},y_{2})$ is the second coordinate).

-Use both points $(-1,2)$ and $(5,5)$ for the formula:

$m = \frac{5-2}{5+1}$

$m = \frac{3}{6}$

$m = \frac{1}{2}$

-After you have found the slope, use the point-slope formula and use the slope $\frac{1}{2}$ and the first coordinate, which is $(-1,2)$, to solve the equation and put it in slope-intercept form:

$y-y_{1} = m (x-x_{1})$

$y-2 = \frac{1}{2} (x+1)$

-Solve:

$y-2 = \frac{1}{2} (x+1)$

$y-2 = \frac{1}{2}x + \frac{1}{2}$

$y = \frac{1}{2}x + \frac{5}{2}$

So, therefore the equation is $y = \frac{1}{2}x + \frac{5}{2}$ .