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o-na [289]
3 years ago
6

A recipe requires 3/8 cup of sugar for each cup of flour used if a baker uses 10 cups of flour what is the total amount of sugar

that will be needed
Mathematics
1 answer:
snow_lady [41]3 years ago
5 0

Answer:

He would have to use 3\frac{6}{8} (simplified form 3\frac{3}{4}).

Step-by-step explanation:

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Write an equation ​(a) in​ slope-intercept form and ​(b) in standard form for the line passing through ​(​-2,4​) and parallel to
strojnjashka [21]
-1/3x + 10/3 I think is ur answer
8 0
2 years ago
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Rudiy27

Answer:

  A. $4,960

  B. 8%

  C. $120

Step-by-step explanation:

<u>Part A</u>

The amount in the account at the end of 3 years is the original amount ($4000) plus the earned interest ($960). That sum will be ...

  $4,000 + 960 = $4,960 . . . account balance

__

<u>Part B</u>

The amount of interest is computed using the formula ...

  I = Prt

where I is the interest earned, P is the principal invested, r is the annual rate, and t is the number of years. Putting the given values into this equation, we can solve for r:

  960 = 4000·r·3

  960/12000 = r = 0.08 = 8%

The interest rate was 8%.

__

<u>Part C</u>

The additional interest can be computed using the same formula as for part B.

  I = Prt

  I = 4000·0.01·3 = 120

The additional interest earned at a 1% higher rate would be $120.

7 0
4 years ago
Harry Julie’s best friend also paid $25.00 for three T-shirt’s at the sale at JCPenny the sale price saved harry 30% of the orig
Rasek [7]

30%25=7.5

25-7.5=17.5

So the original price of Harry's three T-shirts will be $17.50

5 0
4 years ago
Chau's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Chau $5.50 per pound, and type B
Anettt [7]

84 pounds of Type B coffee is used

<em><u>Solution:</u></em>

Let "x" be the pounds of type A coffee

Let "y" be the pounds of type B coffee

Cost per pound of type A = $ 5.50

Cost per pound of Type B = $ 4.20

<em><u>This month, Chau made 143 pounds of the blend</u></em>

x + y = 143

x = 143 - y -------- eqn 1

<em><u>For a total cost of $677.30. Thus we frame a equation as:</u></em>

pounds of type A coffee x Cost per pound of type A + pounds of type B coffee x Cost per pound of Type B = 677.30

x \times 5.50 + y \times 4.20 = 677.30\\\\5.5x + 4.2y = 677.30 -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 1 in eqn 2</u></em>

5.5(143-y) +4.2y = 677.30\\\\786.5 -5.5y + 4.2y = 677.30\\\\5.5y - 4.2y = 786.5 - 677.30\\\\1.3y = 109.2\\\\Divide\ both\ sides\ by\ 1.3\\\\y = 84

Thus 84 pounds of Type B coffee is used

8 0
3 years ago
Solve the proportions.
EleoNora [17]

Answer:

12. n = 8

13. t = 308

14. k = 5

Step-by-step explanation:

12. 2/3 = n/12

Multiply by 4 because 3×4 = 12

So, n = 8

13. 33/t = 3/28

Multiply by 11 because 3×11 = 33

So, t = 308

14. k/6 = 15/18

Multiply by 3 because 6×3 = 18

So, 3k = 15. k = 5

8 0
4 years ago
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