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Dahasolnce [82]
3 years ago
11

Find the solutions for a triangle with a = 16, c =12, and B = 63º.

Mathematics
1 answer:
maks197457 [2]3 years ago
6 0

Answer:

b. A = 71.6°; C = 45.40°; b =15.0

Step-by-step explanation:

The missing values can be found with the help of the Law of Cosine and properties of triangles:

Side b (Law of Cosine)

b = \sqrt{a^{2}+c^{2}-2\cdot a \cdot c \cdot \cos B}

b = \sqrt{16^{2}+12^{2}-2\cdot (16)\cdot (12) \cdot \cos 63^{\circ}}

b \approx 15.022

Angle A (Law of Cosine)

\cos A = -\frac{a^{2} - b^{2}-c^{2}}{2\cdot b \cdot c}

\cos A = - \frac{16^{2}-15.022^{2}-12^{2}}{2\cdot (15.022)\cdot (12)}

\cos A = 0.315

A= \cos^{-1} 0.315

A \approx 71.639^{\circ}

Angle C (Sum of internal angles in triangles)

C = 180^{\circ} - 63^{\circ} - 71.639^{\circ}

C = 45.361^{\circ}

Hence, the right answer is B.

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