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ValentinkaMS [17]
3 years ago
8

PLSSSSSS HELP BRAINLIST

Mathematics
1 answer:
Helga [31]3 years ago
4 0

Answer:

The step 4 is not what he should have done. But the wrong is step 5, because if he added -2x both sides, it would give the following equation:

x-12=-4x+6

and not x-12=6

Note that in step 4 he should have added 2x and not -2x to both sides, but we still have the equality. The problem is that step 5 is totally wrong.

I don't know what answer is expected to this question, but I would mark step 5, because this is mathematically wrong.  

Solving the equation

3(x-4)=-4-2(x-5)

Using distribution

3x-12=-4-2x+10\\3x-12=-2+6

Add 2x both sides

3x-12+2x=-2x+6+2x

5x-12=6

Add 12 both sides

5x-12+12=6+12\\5x=18

Divide both sides by 5

$x=\frac{18}{5} $

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The function f(x)=501170(0.98)x gives the population of a Texas City x years after 1995. What was the population in 1995?
galina1969 [7]

Answer:

The population of a Texas City in 1,995 was 501,170\ people

Step-by-step explanation:

we have

f(x)=501,170(0.98^{x})

we know that

The population in 1,995 is for x=0

so

substitute the value of x=0 in the function f(x)

f(0)=501,170(0.98^{0})=501,170\ people

4 0
4 years ago
hi, I need help on this math problem. I'm working on two step equations but I don't remember how to do these type of problems. t
Mazyrski [523]
The 5’s cancel each other out, so you’re just left with a on that side, meaning -3=a.

4 0
4 years ago
A flat rectangular piece of aluminum has a perimeter of 62 inches. The length is 15
Salsk061 [2.6K]

Answer:

So, the required width of rectangular piece of aluminium is 8 inches

Step-by-step explanation:

We are given:

Perimeter of rectangular piece of aluminium = 62 inches

Let width of rectangular piece of aluminium = w

and length of rectangular piece of aluminium  = w+15

We need to find width i.e value of x

The formula for finding perimeter of rectangle is: Perimeter=2(Length+Width)\\

Now, Putting values in formula for finding Width w:

Perimeter=2(Length+Width)\\\\62=2(w+15+w)\\62=2(2w+15)\\62=4w+30\\62-30=4w\\4w=32\\w=\frac{32}{4}\\w=8

After solving we get the width of rectangular piece :w = 8

So, the required width of rectangular piece of aluminium is 8 inches

6 0
3 years ago
Calcule:
Serggg [28]

a) -5

b)-5

c)3

d)-5

e)2

f)9

g)12

4 0
3 years ago
Mrs. Bowlin organized the markers into sets. If there were 9 markers
Annette [7]

Answer:

  63 sets

Step-by-step explanation:

  (567 markers)/(9 markers/set) = 567/9 sets = 63 sets

__

The total number of markers in all the sets (s) will be ...

  9s = 567

Divide both sides of this equation by 9 to find the number of sets:

  9s/9 = 567/9

  s = 63

Mrs. Bowlin created 63 sets of markers.

6 0
3 years ago
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