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abruzzese [7]
3 years ago
6

A ladder is leaning against a house at an angle of 39°. If the latter is 12 feet long, how far is the bottom of the ladder from

the house?

Mathematics
2 answers:
velikii [3]3 years ago
8 0

Answer: 9.32 ft

Step-by-step explanation:

Hi, since the situation forms a right triangle (see attachment) we have to apply the next trigonometric function.  

Cos α = adjacent side / hypotenuse  

Where α is the angle of elevation of the ladder to the ground, the hypotenuse is the longest side of the triangle (in this case is the length of the ladder), and the adjacent side (x) is the distance between the bottom of the ladder and the house.

Replacing with the values given:  

cos 39 = x/ 12

Solving for x  

cos39 (12) =x  

x= 9.32 ft

Feel free to ask for more if needed or if you did not understand something.  

VashaNatasha [74]3 years ago
6 0

Answer:

The bottom of the ladder is 7.55 feet far away from the house

Step-by-step explanation:

To find the distance between the bottom of the ladder from a house if a ladder of 12 feet long   is leaning against a house at an angle of 39°, then we will follow the steps below:

We can use trig ratios to find the solution to this problem

SOH CAH  TOA

sinФ= opposite/hypotenuse

cosФ=adjacent/hypotenuse

tanФ=opposite /adjacent

from the diagram below;

angle Ф=39°

hypotenuse =12 feet

opposite = x        where x is the distance of the bottom of the ladder from the house

Given these parameter, the best trig function to use sine

sinФ =  opposite / hypotenuse

sin 39° = \frac{X}{12}

cross-multiply

x = 12 sin 39

x ≈ 7.55 feet

Therefore, the bottom of the ladder is 7.55 feet far away from the house

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Step-by-step explanation:

Ok, so in order to solve this, it would be easier to substitute (a,b) into the equation:

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Part b) \$20,442.36

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Step-by-step explanation:

we know that  

The compound interest formula is equal to

A=P(1+\frac{r}{n})^{nt}

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Part a) How much would you have at the end of 1 year?

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Part b) How much would you have at the end of 2 year?

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A=15,192(1+\frac{0.16}{1})^{1*3}=\$23,713.13

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in this problem we have

t=4\ years\\ P=\$15,192\\ r=0.16\\n=1

substitute in the formula above

A=15,192(1+\frac{0.16}{1})^{1*4}=\$27,507.23

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