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pychu [463]
2 years ago
8

What do the solutions of a quadratic represent graphically?

Mathematics
1 answer:
asambeis [7]2 years ago
8 0

Answer:

c

Step-by-step explanation:

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Simplify (2 x 10^3) (4 x 10^-5)
Vlad [161]

the answer to this problem is 2/25. I got this by simplifying both exponents which changes the equation to (2)(1000)(4)(1/100000). Then you multiply the other numbers by its simplified exponent and makes the equation 2000(1/25000). The last step is to multiply those two and you get your answer, 2/25(simplified version)   :)

8 0
3 years ago
Ben has $100 to go shopping. Does he have enough money to buy a $20 and a $72 pair of shoes if there is an 8.5% tax
Juli2301 [7.4K]

So, we first add the 20 and 72 together and you will get 92.

What I like to do next is usually 92/100x8.5. The tax would be then 7.82

92 + 7.82 = 99.82 < 100

The answer is yes.

7 0
3 years ago
Which of the following is not a correct way to represent the ratio 5 to 2 a)2/5 c)5:2 b)5/2 d) 10:4
lianna [129]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Given that MN = 5, NO = 12, and MO = 13, find cos O.
Galina-37 [17]

Answer:

12/13

Step-by-step explanation:

Given that MN = 5, NO = 12, and MO = 13, find cos O.

Since the reference angle is P, hence;

MN is the opposite = 5

MO is the hypotenuse = 13 (longest side)

NO is the adjacent = 12

Cos O = adj/hyp

Substitute the given values

Cos O = 12/13

Hence the value of Cos O is 12/13

8 0
3 years ago
Congruent triangles &amp; proofs need answers to all the ones i got wrong. thank u!
notka56 [123]

Answer:

Step-by-step explanation:

13. Since, it is given that we have to prove ΔGDH≅ΔFEH by HL rule, thus From ΔGDH, ∠GDH=90° and GH is the hypotenuse and from ΔFEH, ∠HEF=90° and HF is the hypotenuse, thus in ΔGDH and ΔFEH,

∠GDH≅∠HEF=90°

GH≅FH,

Thus by HL the given triangles are congruent.

Option A is correct.

14. From the figure, it can be seen that both triangles have a right angle congruent and hypotenuse congruent, thus by HL rule, triangle scan be prove congruent.

Option A is correct.

15. It is given that BI is parallel to RD, thus using the alternate interior angle property, ∠B≅∠R.

Option C is correct.

16. It is given that BI is parallel to RD, and ∠BSI and ∠RSD form the vertically opposite angles, thus ∠BSI≅∠RSD by vertical angles are congruent.

Option A is correct.

17. Since Δ ABC is an isosceles triangle, thus two sides of the triangle are equal, therefore ∠A=∠B=3x+5, using the angle sum property in ΔABC, we have

3x+5+2x+3x+5=180°

⇒8x+10=180

⇒8x=170

⇒x=21.25

Thus, ∠B=3x+5=3(21.25)+5=63.75+5=68.75°

18. From ΔJKL and ΔDEF, we have

∠K=∠E (given)

∠L=∠F(given)

JL=DF

Thus, By AAS rule ΔJKL ≅ ΔDEF

As corresponding angles and corresponding sides are equal in these two triangles as compared to the other triangles.

8 0
3 years ago
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