1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
My name is Ann [436]
3 years ago
7

Which of the following are interactions between particles in a liquid?

Chemistry
1 answer:
Artemon [7]3 years ago
8 0
Can you pick more than one?
You might be interested in
1. john needs to create a buffered solution at a ph of 3.5 for his biomedical laboratory
Lunna [17]

Answer:

Use a ratio of 0.44 mol lactate to 1 mol of lactic acid  

Explanation:

John could prepare a lactate buffer.

He can use the Henderson-Hasselbalch equation to find the acid/base ratio for the buffer.

\text{pH} = \text{pK}_{\text{a}} + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}\\\\3.5 = 3.86 + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}\\\\\log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}} = 3.5 - 3.86 = -0.36\\\\\dfrac{\text{[A$^{-}$]}}{\text{[HA]}} = 10^{-0.36} = \mathbf{0.44}

He should use a ratio of 0.44 mol lactate to 1 mol of lactic acid.

For example, he could mix equal volumes of 0.044 mol·L⁻¹ lactate and 0.1 mol·L⁻¹ lactic acid.

6 0
3 years ago
What is the molar mass of sodium phosphate, Na3PO4?
baherus [9]

Answer:

164g

Explanation:

3×23+31+16×4

≈69+31+64

≈164.0 g

8 0
3 years ago
Label the following changes as Physical or
Leno4ka [110]

Answer:

17

Two clear liquids mix and form a

white solid

18.chemical

A pot of water begins to

boil

19.Physical

the rest im usure on.

5 0
3 years ago
What is the energy of a moving mass?
satela [25.4K]

Answer:

Kinetic energy

Explanation:

This is the energy possessed by a moving object.

6 0
3 years ago
Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 30.0 °C for the following reacti
gayaneshka [121]

Answer : The value of K for this reaction is, 2.6\times 10^{15}

Explanation :

The given chemical reaction is:

CH_3OH(g)+CO(g)\rightarrow HCH_3CO_2(g)

Now we have to calculate value of (\Delta G^o).

\Delta G^o=G_f_{product}-G_f_{reactant}

\Delta G^o=[n_{HCH_3CO_2(g)}\times \Delta G^0_{(HCH_3CO_2(g))}]-[n_{CH_3OH(g)}\times \Delta G^0_{(CH_3OH(g))}+n_{CO(g)}\times \Delta G^0_{(CO(g))}]

where,

\Delta G^o = Gibbs free energy of reaction = ?

n = number of moles

\Delta G^0_{(HCH_3CO_2(g))} = -389.8 kJ/mol

\Delta G^0_{(CH_3OH(g))} = -161.96 kJ/mol

\Delta G^0_{(CO(g))} = -137.2 kJ/mol

Now put all the given values in this expression, we get:

\Delta G^o=[1mole\times (-389.8kJ/mol)]-[1mole\times (-163.2kJ/mol)+1mole\times (-137.2kJ/mol)]

\Delta G^o=-89.4kJ/mol

The relation between the equilibrium constant and standard Gibbs, free energy is:

\Delta G^o=-RT\times \ln K

where,

\Delta G^o = standard Gibbs, free energy  = -89.4 kJ/mol = -89400 J/mol

R = gas constant  = 8.314 J/L.atm

T = temperature  = 30.0^oC=273+30.0=303K

K = equilibrium constant = ?

Now put all the given values in this expression, we get:

-89400J/mol=-(8.314J/L.atm)\times (303K)\times \ln K

K=2.6\times 10^{15}

Thus, the value of K for this reaction is, 2.6\times 10^{15}

4 0
4 years ago
Other questions:
  • Eating of candy is a chemical change? How
    8·1 answer
  • How to find the number of moles in a molecule of water
    8·1 answer
  • Please help I need a 100
    7·2 answers
  • If 20 ml of gas is subjected to a tempature change from 10 Celsius to 100 Celsius and a pressure change from 1 atm to 10 atm, th
    9·1 answer
  • The______ the forces among the particles in a sample of matter, the more rigid the matter will be.
    6·1 answer
  • Ravi cow gives 2 1/4 gallon Milk each day . How much is this in quarts
    6·1 answer
  • What is a gas quick!
    5·1 answer
  • Which statements describe or apply the principal of conservation of energy? Select all that apply.
    5·2 answers
  • At the end of an experiment your expected amount of product was 35 grams, but you only produced 32 grams. Calculate the percent
    6·1 answer
  • 1. Given the following equation:
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!