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brilliants [131]
3 years ago
10

Help me solve this please. The bottom one

Mathematics
1 answer:
Nesterboy [21]3 years ago
7 0
The answers is c......
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Eleanor deposits 20% of the money that she earns each week in a savings account. If Eleanor earns $85 each week, how much money
RoseWind [281]

Answer:

She will deposit $17.

Step-by-step explanation:

So this is really simple.

20% of $85= 0.20•85= 17=$17

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What it 7 divided by 8 in decimal form
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Seven divided by eight is 0.88 or 0.875
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If you flipped the graph y=x^2+2x-2 vertically, you would get the graph y=-(x^2 +2x-2). true or false
Mars2501 [29]
If you flipped the graph y=x^2+2x-2 vertically, you would get the graph y=-(x^2+2x-2) this is True. 
5 0
3 years ago
8. A substance has a half life of 2.347 minutes.
mina [271]

Answer:

a.) 4 half lives have passed

b) 9.388 minutes

Step-by-step explanation:

Formula for exponential growth / decay is given as:

A=A_0b^{\frac{t}{c}}

Where A is the final population

A_0 is the initial population

b is the growth factor

c is the time taken for the growth 'b'

t is the amount of time

Here, we are given that:

A = 6. 9 grams

A_0 = 110.4 grams

b = \dfrac{1}{2}

c = 2.347 min

To find:

a.) Number of half lives taken for the decay.

b.) Total time in the decay.

Solution:

a.) Number of half lives taken for the decay is nothing but equal to \frac{t}{c}.

Putting the values in the formula, we get:

6.9=110.4\times \frac{1}2^{\frac{t}{c}}\\\Rightarrow 6.9=110.4\times 0.5^{\frac{t}{c}}\\\Rightarrow 0.0625=0.5^{\frac{t}{c}}\\\Rightarrow \dfrac{t}{c} =4

Therefore, the answer is:

<em>4 half lives </em>have passed.

b.) Total time of decay. We have to find the value of t here.

From answer of part a.):

\dfrac{t}{c} =4\\\Rightarrow \dfrac{t}{2.347} =4\\\Rightarrow t =\bold{9.388\ min}

7 0
3 years ago
Help me with this problem
vova2212 [387]

Answer:

The answer is 180 - 65

Step-by-step explanation:

We got 180, because that is the number of degree's in a line

so 180 - 65 is 115 degrees, that's your answer :)

7 0
3 years ago
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