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mixer [17]
3 years ago
14

The Venn diagram compares and contrasts two of the biological domains. Based on the information provided, what domain would best

be represented by circle A?
A) Archaea because it contains bacteria that do not live in extreme conditions.
B) Eukarya because it contains bacteria that do not live in extreme conditions.
C) Bacteria because it contains bacteria that do not live in extreme conditions.
D) Eubacteria because it contains bacteria that do not live in extreme conditions.

Biology
2 answers:
Nitella [24]3 years ago
8 0

Answer:

All answers should be fine except C

Explanation:

A, B, and D are all types of bacteria while C is refering to bacteria itself when it has many factors. I suggest researching each bacteria for its factors but it's just a suggestion.

Shkiper50 [21]3 years ago
5 0

Answer:

C) Bacteria because it contains bacteria that do not live in extreme conditions.

Explanation:

Bacteria in domain Bacteria live in the soil, water, bodies of humans and animals, but not extreme environments.

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When referring to height in terms of genotypes, is there a reason why V and v are used to commonly represent the alleles?
Flura [38]

Answer:

Explanation:

Geneticists use letters to represent alleles of different characters.

(Alleles: one of the two or more alleles  of a character.)

A single letter is used to represent both the alleles of a particular character.

A capital letter represents a dominant allele, while a small letter represents a recessive one.

<u>The letters do not just have one standard representation</u>. same letter can be used to represent different characters. However, the letters may relate to the allele. For example: the letter 'B' can be used to represent Brown eyes.

8 0
3 years ago
You splice DNA fragments from a "foreign" source into the patient's gene so that the gene will begin manufacturing the enzyme. T
Arada [10]

Answer:

recombinant DNA

Explanation:

In molecular biology, recombinant DNA molecules are genetic sequences formed by combining DNA material from different sources (i.e., organisms, populations, species, etc). Proteins produced from DNA recombinant molecules are known as recombinant proteins. Molecular cloning is the most widely used technique in molecular biology in order to produce recombinant DNA molecules. In this technique, a cloning vector such as, for example, a plasmid of a bacterium, is used to insert a foreign DNA fragment into another cell which is then expressed in the host cell.

3 0
2 years ago
An individual cell is able to make copies of its genetic information but it's unable to produce encoded proteins. this indicates
eduard
This indicates a possible problem with the ribosome of the cell. Ribosomes in cells are responsible for translation the genetic codes in mRNA to appropriate proteins with the help of tRNA. mRNA, rRNA, tRNA and ribosome work together during protein synthesis to produce chains of amino acids that are linked together by polypeptide bonds.
7 0
3 years ago
The retinoblastoma protein, pRB, is a tumor-suppressor protein that controls the G1/S cell-cycle checkpoint. While pRB is presen
gladu [14]

Answer:

1. pRB phosphorylated: The cell will not remain in G1 phase i.e. it will enter S phase because pRB will be degraded.

2. pRB not phosphorylated: The cell will remain in G1 phase i.e. will not enter S phase because pRB will remain bound to E2F.

3. pRB bound to E2F: The cell will remain in G1 phase i.e. will not enter S phase.

4. pRB not bound to E2F: The cell will not remain in G1 phase i.e. it will enter S phase.

5. E2F bound to DNA: The cell will not remain in G1 phase i.e. it will enter S phase.

6. CDK4 bound to Cyclin D1:  The cell will not remain in G1 phase i.e. it will enter S phase.

Explanation:

Retinoblastoma protein, pRB supresses tumor by regulating cell cycle progression in G1 phase. When a transcription factor known as E2F is bound to pRB the cell remains in G1 phase and did not proceed further to enter S phase. But as soon as pRB becomes phosphorylated, E2F becomes free and causes gene expression of cyclin E and and cyclin A which are required in progression of cell cycle from G1 phase to S phase.

<u>Signaling involved in cell cycle progression from G1 phase to S phase. </u>

When a cell is unstimulated, pRB is bound to E2F but G1 phase specific growth factors induce the expression of cyclin D through Ras-MAP kinase pathway.

Synthesis of cyclin D leads to the activation of CDK-4 which is a serine-threonine kinase. This kinase causes phosphorylation of pRB which results in the degradation of pRB.

Because of degradation of pRB, <u>E2F becomes free</u> and leads to the expression of cyclin E and and cyclin A which are S phase specific cyclins. This is how cell progresses from G1 phase to S phase.

E2F is a transcription factor which causes expression of S phase specific cyclins i.e. cyclin E and and cyclin A. So, E2F bound to DNA will result in cell cycle progression from G1 phase to S phase.

7 0
3 years ago
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