All categories

3 years ago

What is the domain of this function?

Mathematics

1 answer:

frutty [35]3 years ago

3 0

Answer:

Step-by-step explanation:

The closed dot at (0, 9) indicates that that's where the graph begins. The arrow at the other end indicates that it has no end. Since the domain covers x values only (NOT Y VALUES!), we only need be concerned with the x values. It starts at x = 0 and never ends, so the domain is properly stated as

{x | x ≥ 0}

You might be interested in

Which steps will generate an expression equivalent to 17(x+5)?<br> MARK BRAINLIEST

bezimeni [28]

Answer:

multiply 17x5=85,85+5=90 so aswer is 90

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis. Verify y

Drupady [299]

Answer:

$V = \frac{\pi^2}{8}$

$V = 1.23245$

Step-by-step explanation:

Given

$y = \cos 2x$

$y = 0; x = 0; x = \frac{\pi}{4}$

Required

Determine the volume of the solid generated

Using the disk method approach, we have:

$V = \pi \int\limits^a_b {R(x)^2} \, dx$

Where

$y = R(x) = \cos 2x$

$a = \frac{\pi}{4}; b =0$

So:

$V = \pi \int\limits^a_b {R(x)^2} \, dx$

Where

$y = R(x) = \cos 2x$

$a = \frac{\pi}{4}; b =0$

So:

$V = \pi \int\limits^a_b {R(x)^2} \, dx$

$V = \pi \int\limits^{\frac{\pi}{4}}_0 {(\cos 2x)^2} \, dx$

$V = \pi \int\limits^{\frac{\pi}{4}}_0 {\cos^2 (2x)} \, dx$

Apply the following half angle trigonometry identity;

$\cos^2(x) = \frac{1}{2}[1 + \cos(2x)]$

So, we have:

$\cos^2(2x) = \frac{1}{2}[1 + \cos(2*2x)]$

$\cos^2(2x) = \frac{1}{2}[1 + \cos(4x)]$

Open bracket

$\cos^2(2x) = \frac{1}{2} + \frac{1}{2}\cos(4x)$

So, we have:

$V = \pi \int\limits^{\frac{\pi}{4}}_0 {\cos^2 (2x)} \, dx$

$V = \pi \int\limits^{\frac{\pi}{4}}_0 {[\frac{1}{2} + \frac{1}{2}\cos(4x)]} \, dx$

Integrate

$V = \pi [\frac{x}{2} + \frac{1}{8}\sin(4x)]\limits^{\frac{\pi}{4}}_0$

Expand

$V = \pi ([\frac{\frac{\pi}{4}}{2} + \frac{1}{8}\sin(4*\frac{\pi}{4})] - [\frac{0}{2} + \frac{1}{8}\sin(4*0)])$

$V = \pi ([\frac{\frac{\pi}{4}}{2} + \frac{1}{8}\sin(4*\frac{\pi}{4})] - [0 + 0])$

$V = \pi ([\frac{\frac{\pi}{4}}{2} + \frac{1}{8}\sin(4*\frac{\pi}{4})])$

$V = \pi ([{\frac{\pi}{8} + \frac{1}{8}\sin(\pi)])$

$\sin \pi = 0$

So:

$V = \pi ([{\frac{\pi}{8} + \frac{1}{8}*0])$

$V = \pi *[{\frac{\pi}{8}]$

$V = \frac{\pi^2}{8}$

$V = \frac{3.14^2}{8}$

$V = 1.23245$

4 0

3 years ago

Joe is saving money for his

tatyana61 [14]

Answer:

He will need to save $295

Step-by-step explanation:

he needs 450 and he has 155, so all you would do is subtract 155 from 450 and you get the rest he needs which is 295

6 0

2 years ago

a total of 4 freinds ate lunch at a cafe. they decided to split the bill wvenly. the total bill was $17.84. how much was each pe

ivann1987 [24]

So that would be the total bill divided by 4
17.84/4=16/4+1/4+0.84/4=4+0.25+0.21=4.46

each person's share was $4.46

7 0

4 years ago

Please help me. I desperately need to pass Math T-T

Ad libitum [116K]

Answer:

60 degrees

Step-by-step explanation:

C = 2(pi)r

The radius is 12 cm. We can find the circumference of a circle with radius 12 cm.

C = 2(pi)r = 2(3.14)(12 cm) = 75.36 cm

The length of the arc of the sector is 12.56 cm.

We can find the fraction this length is of the full circumference.

(12.56 cm)/(75.36 cm) = 1/6

The length of the arc of this sector is 1/6 the length of the circumference of the entire circle.

That means the angle of the sector is 1/6 the angle of an entire circle.

An entire circle has a central angle of 360 degrees.

1/6 * 360 degrees = 60 degrees

4 0

3 years ago