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3 years ago

Help Will Award brainliest

Mathematics

2 answers:

trapecia [35]3 years ago

6 0

Answer:

c 6 1 \ 20

Step-by-step explanation:

laila [671]3 years ago

5 0

The answer to your question is C. 6^1/20

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Find the sum of the first ten prime numbers. Find the sum of the first ten prime numbers .

natali 33 [55]

The sum of the first ten prime numbers is 129.

<h3>What is a prime number?</h3>

The prime numbers are those numbers that have only one factor namely 1 and the number itself.

The first 10 prime numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23, and 29.

Their sum is

2 + 3 + 5 + 7 + 11 + 13 + 17 + 19 + 23 + 29

= 129

Hence, the sum of the first ten prime numbers is 129.

Learn more about prime numbers;

brainly.com/question/4184435

#SPJ1

5 0

2 years ago

When working in the GreenHab, it takes me 120 minutes to report 20 tomato plants. How many plants can I report in 30 minutes?

Lyrx [107]

Answer:

Numbers of Tomato plants to be reported in 30 minutes = 5 unit

Step-by-step explanation:

It is given that ,

Time taken to report 20 Tomato plants (P1) = 120 minutes (T1)

Let number of plants to be reported in 30 minutes (T2) = P2

Now , $\frac{T2}{P2} = \frac{T1}{P1}$

$\frac{30}{P2} = \frac{120}{20}$

So, P2 = 5 unit

Hence the number of plant to be reported in 30 minutes = 5 unit Answer

4 0

3 years ago

HELP ME!!!!!!

Dmitry_Shevchenko [17]

Answer:

The answer is C

Step-by-step explanation:

7 0

4 years ago

A tree was 14 3/8 inches tall when it was first planted. Two years later, the tree was 21 1/8 inches tall. how much did the tree

Oxana [17]

Answer:

In two years, the tree grew 27/4in.

Step-by-step explanation:

21 1/8 - 14 3/8 = 27/4in.

hope it helped :)

mark me brainliest!

7 0

3 years ago

Please solve the problem

jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2X + Y = A and 3X - 4Y = B.

Then you can eliminate Y by taking the sum

4A + B = 4 (2X + Y) + (3X - 4Y) = 11X

==> X = (4A + B)/11

Similarly, you can eliminate X by using

-3A + 2B = -3 (2X + Y) + 2 (3X - 4Y) = -11Y

==> Y = (3A - 2B)/11

It follows that

$X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}$

Similarly, you would find

$Y=\begin{bmatrix}2&1\\4&4\end{bmatrix}$

You can solve the second system in the same fashion. You would end up with

$P=\begin{bmatrix}2&-3\\0&1\end{bmatrix} \text{ and } Q=\begin{bmatrix}1&2\\3&-1\end{bmatrix}$

3 0

3 years ago