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Cloud [144]
3 years ago
5

Tyrell is a landscape architect. For his first public project, he is asked to create a small-scale drawing of a garden to be pla

ced in the corner of a city park. The garden is a right triangle with a base of 25 m and a height of 30 m. The scale is 1 inch = 5 meters. What are the dimensions of the scale drawing of the garden?
*HINT: Set up two proportions to find the length of the BASE and the length of the HEIGHT of the triangular garden.
A. 125-inch base; 150-inch height

B. 1-inch base; 5-inch height

C. 10-inch base; 15-inch height

D. 5 inch base; 6 inch height
Mathematics
1 answer:
dezoksy [38]3 years ago
7 0

Answer:

D. is correct!

Step-by-step explanation:

ht tps://us-static.z-dn.net/fil es/ded/302e17a93f9f7dceb0b9635c302342ae.jp g

^ just an example

brainliest?

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Which key correctly represents the information below? A. 11 | 2 = 12 B. 1 | 2 = 12 C. 11 | 2 = 112 D. 11 | 2 = 13
Alisiya [41]

Answer:

The answer is (B) 1/2=12

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What is 7/4 as a mixed number?<br> a. 17/4<br> b. 3/4<br> c. 13/4<br> d. 11/4
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Find the LCM of 210, 280, 360 by prime factorisation​
Katyanochek1 [597]

Answer:

Step-by-step explanation:

210=2x3x5x7

280=2x2x2x5x7

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4 years ago
Consider this equation. Cos(0) = 8/9 if 0 is an angle in quadrant IV, what is the value of tan(0)? I
Vinvika [58]

Answer:

\displaystyle \tan(\theta)=-\frac{\sqrt{17}}{8}

Step-by-step explanation:

We are given that:

\displaystyle \cos(\theta)=\frac{8}{9}

Where θ is in QIV.

And we want to find the value of tan(θ).

Recall that cosine is the ratio of the adjacent side over the hypotenuse.

Therefore, the opposite side is:

o=\sqrt{9^2-8^2}=\sqrt{17}

Next, in QIV, only cosine is positive: sine and tangent are both negative.

Tangent is the ratio of the opposite side to the adjacent. So:

\displaystyle \tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}

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\displaystyle \tan(\theta)=-\frac{\sqrt{17}}{8}

3 0
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