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Cloud [144]
3 years ago
5

Tyrell is a landscape architect. For his first public project, he is asked to create a small-scale drawing of a garden to be pla

ced in the corner of a city park. The garden is a right triangle with a base of 25 m and a height of 30 m. The scale is 1 inch = 5 meters. What are the dimensions of the scale drawing of the garden?
*HINT: Set up two proportions to find the length of the BASE and the length of the HEIGHT of the triangular garden.
A. 125-inch base; 150-inch height

B. 1-inch base; 5-inch height

C. 10-inch base; 15-inch height

D. 5 inch base; 6 inch height
Mathematics
1 answer:
dezoksy [38]3 years ago
7 0

Answer:

D. is correct!

Step-by-step explanation:

ht tps://us-static.z-dn.net/fil es/ded/302e17a93f9f7dceb0b9635c302342ae.jp g

^ just an example

brainliest?

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Solve the equation below for x. −12(3x−4)=11 A. −1323 B. −813 C. −6 D. 6
geniusboy [140]

-1/2( 3x -4) = 11

Use distributive properties:

-3/2 + 2,= 11

Subtract 2 from both sides:

-3/2x = 9

Divide both sides by -3/2

X = 9/ -3/2

X = -6

The answer is c. -6

3 0
3 years ago
A combinatio of a translations and a reflection can always be replaced with one transformation
Tema [17]

Answer:

It is correct according to the laws

4 0
1 year ago
Which is a factor of 10x - 20x2 - 2x + 4?
sveta [45]
Add like terms and then simplify
7 0
3 years ago
You are making a welding fixture and must cut down a length of copper tubbing from 15 1/8 inches to 8 3/4 inches. If the leftove
fgiga [73]

Answer: 51/8 inches

Step-by-step explanation:

Since you must cut down the length of copper tubbing from 15 1/8 inches to 8 3/4 inches, the leftover piece will be:

15 1/8 - 8 3/4

Change the mixed fraction to improper fraction.

121/8 - 35/4

The LCM will be 8

( 121 - 70 )/8

51/8 or 6.375 inches

Therefore, the leftover piece will be 51/8 inches long

7 0
4 years ago
A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student
umka2103 [35]

Answer:

(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908  

(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308  

So then the confidence interval for the difference of means is given by:

-8.908 \leq \mu_M -\mu_F \leq 5.308

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X_{M}= 69.8 represent the mean for the age of grandmother

\bar X_{F}= 71.6 represent the mean for the age of grandfather

s_{M}= 8.38 represent the sample deviation for the age of grandmother

s_{F}= 6.65 represent the sample deviation for the age of grandfather

n_M = n_F= 10

Solution to the problem

For this case the confidence interval is given by:

(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n_M +n_F-2=10+10-2=18

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that t_{\alpha/2}=2.101

And replacing we got:

(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908  

(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308  

So then the confidence interval for the difference of means is given by:

-8.908 \leq \mu_M -\mu_F \leq 5.308

5 0
3 years ago
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