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Nataliya [291]
3 years ago
12

Simplify the expression given below. x+2/x^3+2x^2

Mathematics
1 answer:
sp2606 [1]3 years ago
8 0

Answer:

\frac{2x^{5} +x^{4}+2 \\}{x^{3} }

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What is the answer to this: 5•k•(-7); k=3/5?
oksano4ka [1.4K]
This is simple:

If k=3/5, then you substitute 3/5 for k

Example:
5(3/5)(-7)=?
Answer: -175/3 or -58.33 repeating

3 0
3 years ago
In a probability experiment Eric flipped a coin 30 times the coin landed on heads 20 times what is the ratio of heads to tails i
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Answer:

it would 600

Step-by-step explanation:

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Pete moran bought a dell laptop computer priced at $699. he put down 30%. the amount of the down payment is:
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209.70 because 699/100*30=209.70

5 0
3 years ago
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Mr.Ronaldo earns 46,650 in annual gross income. He will pay 7% in income tax this year. What is the amount of income tax that Mr
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Hey there!

To find the amount of tax, we simply multiply 0.07 (the percentage) by his income.

0.07*46650=3265.5

Therefore, he will pay $3,265.50 in income tax.

I hope this helps!

8 0
3 years ago
A random sample of 20 healthy adults was collected and their body temperatures were measured in degrees Fahrenheit. The data can
castortr0y [4]

Answer:

Step-by-step explanation:

Hello!

You need to test the hypothesis that "the average temperature for healthy adults is not equal to 98.6"

The variable of interest is

X: The body temperature of a healthy adult. (Fahrenheit)

And the parameter of interest is the population mean, μ.

The statistic hypotheses are:

H₀: μ = 98.6

H₁: μ ≠ 98.6

α:0.05

Assuming that the variable has a normal distribution you have to use a one-sample t-statistic for this test.

Attached to the answer is the data of body temperature of n=19 healthy adults. Since you didn't copy the raw data for your exercise I'll use this to answer the question.

Using the data the sample mean and standard deviation are:

X[bar]= 98.12

S= 0.69

t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~~t_{n-1}

t_{H_0}= \frac{98.12-98.6}{\frac{0.69}{\sqrt{19} } } = -3.03

This test is two-tailed, using the critical value approach, you have the rejection region divided into two tails determined by two critical values:

t_{n-1;\alpha /2}= t_{18;0.025}= -1.965

t_{n-1;1-\alpha /2}= t_{18;0.975}= 1.965

Decision rule:

If t_{H_0} ≤ -1.965 or if t_{H_0} ≥ 1.965, the decision is to reject the null hypothesis.

If -1.965 < t_{H_0} < 1.965, the decision is to not reject the null hypothesis.

The calculated statistic is less than the lower critical value, the decision is to reject the null hypothesis.

Using a significance level of 5%, there is enough evidence to reject the null hypothesis. Then you can conclude that the true mean body temperature for healthy adults is not equal to the traditional 98.6F.

I hope this helps!

7 0
4 years ago
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