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andrew-mc [135]
3 years ago
14

PLZ HELP ITS DUE TOMORROW

Mathematics
1 answer:
ElenaW [278]3 years ago
3 0

Answer:

1001-70-336=595

Step-by-step explanation:

i think..

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All Major League Baseball stadiums use standard measurements for their infield area. The pitcher's mound is a circle with a diam
denis-greek [22]

Answer:

254 4/7 or 254.34 ft² (it depends on which method you use.)

Step-by-step explanation:

To find the area of a circle, the formula is πr².

I'll use both 22/7 and 3.14 as pi, so I'll end up with two different answers. Just choose the more reliable one.

22/7 version:

22/7 * 9^2

22/7 * 81/1

1782/7

254 4/7 ft²

3.14 version:

3.14 * 9^2

3.14 * 81

314 - (3.14 * 19)

314 - 62.8 + 3.14

251.2 + 3.14

254.34 ft²

As I said, I ended up with two different answers. You also had said not to round my answer, so the 22/7 version has a mixed number.

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3 years ago
If you have 2 pounds of grapes and there $6 how much is 1 pound grapes?
Vikki [24]

Answer:

$3

Step-by-step explanation:

7 0
3 years ago
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PLEASE HELP <3
quester [9]

Answer:

-403/40

or

-10 3/40

or

-10.075

3 0
3 years ago
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Solve log6 22 = log6 (5x – 8) for x
Ahat [919]
I hope this helps you

7 0
3 years ago
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4-13 Students in a management science class have just re- ceived their grades on the first test. The instructor has provided inf
inessss [21]

Answer:

a) y = 0.74x + 18.99; b) 80; c) r = 0.92, r² = 0.85; r² tells us that 85% of the variance in the dependent variable, the final average, is predictable from the independent variable, the first test score.

Step-by-step explanation:

For part a,

We first plot the data using a graphing calculator.  We then run a linear regression on the data.

In the form y = ax + b, we get an a value that rounds to 0.74 and a b value that rounds to 18.99.  This gives us the equation

y = 0.74x + 18.99.

For part b,

To find the final average of a student who made an 83 on the first test, we substitute 83 in place of x in our regression equation:

y = 0.74(83) + 18.99

y = 61.42 + 18.99 = 80.41

Rounded to the nearest percent, this is 80.

For part c,

The value of r is 0.92.  This tells us that the line is a 92% fit for the data.

The value of r² is 0.85.  This is the coefficient of determination; it tells us how much of the dependent variable can be predicted from the independent variable.

3 0
3 years ago
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