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Solnce55 [7]
3 years ago
13

Joseph wants to cover a rectangular box with wrapping paper. The length of the box is 2 feet, its width is 1 foot, and its heigh

t is 1 foot. The cost of wrapping paper is $0.80 per square foot. How much will it cost Joseph to cover the box with wrapping paper?
Mathematics
1 answer:
vesna_86 [32]3 years ago
6 0
We need to find the surface area of the box. For this, we will do 2(L×W) + 2(L×H) + 2(H×W); Since each has a corresponding side, we multiply it by 2.
Let's find it with plugging it in. 
2(2×1) + 2(2×1) + 2(1×1)
4+4+2=10
Now the surface area is 10 ft², let's just multiply .8 by that to find the price.
.8×10= 8
It'll cost $8 for Joseph to cover the box with wrapping paper.
Tell me if this helps!!
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X^2-18x+67=0 Solve the quadratic equation by completing the square.
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Answer:

x = 9 ± √14

Step-by-step explanation:

x² − 18x + 67 = 0

Move the constant to the other side:

x² − 18x = -67

Take half of -18, square it, and add to both sides.

(-18/2)² = (-9)² = 81

x² − 18x + 81 = -67 + 81

x² − 18x + 81 = 14

Factor the perfect square:

(x − 9)² = 14

Solve for x:

x − 9 = ±√14

x = 9 ± √14

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