If x ¤ y = (x + y)² - (x - y)² Then √5 ¤ √5 =

1 answer:

5 0

$x\ \diamond\ y=(x+y)^2-(x-y)^2=x^2+2xy+y^2-(x^2-2xy+y^2)\\\\=x^2+2xy+y^2-x^2+2xy-y^2=4xy\\\\\sqrt5\ \diamond\ \sqrt5=4\cdot\sqrt5\cdot\sqrt5=4\cdot5=20$

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In a certain Algebra 2 class of 29 students, 7 of them play basketball and 14 of them

Mariulka [41]

Answer:

Two possible answers below

Step-by-step explanation:

Probability and Sets

We are given two sets: Students that play basketball and students that play baseball.

It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.

This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

$\displaystyle P=\frac{19}{29}$

P = 0.66

Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:

We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.

Thus, there 19-2=17 students who play only one of the sports. The probability is:

$\displaystyle P=\frac{17}{29}$