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2 years ago

15 + 3t - 5 - 8t what is the ANSWER to this

1 answer:

8 0

15+3t−5−8t=15+3t+−5+−8tCombine Like Terms:=15+3t+−5+−8t=(3t+−8t)+(15+−5)=−5t+10Answer:=−5t+10

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Theresa is 14 years younger than her brother Jonathan. Together, their total age in years is 35. A) How many years old is Theres

ikadub [295]

A) The age of Theresa is 10 years 6 months old

B) Jonathan age is 24 years and 6 months old

Solution:

Given, Theresa is 14 years younger than her brother Jonathan.

Let the age of Theresa be "n" years

Then the age of Jonathan will be "n + 14" years

Together, their total age in years is 35

A) Finding age of Theresa:

Jonathan age + Theresa age = 35

n + 14 + n = 35

2n + 14 = 35

2n = 35 - 14

2n = 21

n = 10.5

So, age of Theresa is 10 years 6 months

B) Finding age of Jonathan

Now, we know that n = 10.5

Then Jonathan age = n + 14 = 10.5 + 14 = 24.5 years

So, Jonathan is 24 years and 6 months old

4 0

3 years ago

At restaurants waiters typically receive tips that average 15% of the customer’s bill. At this rate, which of the following is t

kodGreya [7K]

Answer:

B $12.69

Step-by-step explanation:

Divide 84.63 by 100 to get 1% of the bill and then multiply the answer by 15 for 15% and round it:

$\frac{84.63}{100} \times 15 = 12.6945$

The closest answer would be B $12.69.

3 0

2 years ago

A(n) = -5 = 6(n-1) Find the 12th term in the sequence.

Margarita [4]

Step-by-step explanation:

According to the question a(n) = -5 for all real values of n.

So the 12th term in the sequence is -5.

6 0

3 years ago

How to work out 20% of £54

Alexandra [31]

Answer:

£10.80

Step-by-step explanation:

20% = $\frac{20}{100}$ = 0.2 , then

£54 × 0.2 = £10.80

3 0

2 years ago

Please help me with this

Papessa [141]

Answer:

see attached

Step-by-step explanation:

The grid show the non-possibilities in red, with each number corresponding to the statement that eliminates that choice. The green square (with black text) shows the one combination that is specified already (by statement 4). The lighter green numbers show possible alternatives: first period may be Schiller or English, and room 113 will be the other one. Similarly, Art may be 3rd period or Thomlinson.

These choices (light green 5, light green 6) give rise to four possibilities. Working through them, you run into inconsistencies if you choose Schiller for first period. (Art must be, but can't be, in room 112.) That leaves two possibilities.

Again, you run into inconsistencies if you choose Thomlinson as the Art teacher. (The class in 112 is 2 periods after Xavier's class, not 1.)

Hence, the only viable pair of remaining choices is Schiller in room 113 and art in 3rd period.

The final schedule is shown in the attachment.

_____

Additional comment

When I'm working these on paper, I use an X to mark any impossible combinations, and a circle (O) to mark a known combination. In any given 4×4 square of the grid, the remaining cells of the row and column containing a O must be Xs. Consistency must be maintained between rows and columns. This often means filling a circle in one place may result in a circle being filled in another place. Of course, once 3 of the squares in a row or column have Xs, the remaining one must be O.

6 0

2 years ago