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USPshnik [31]
3 years ago
9

What is the measure of the missing angle in the figure below?

Mathematics
1 answer:
Talja [164]3 years ago
5 0

Answer: x=158\°

Step-by-step explanation:

The picture given in the exercise shows a Quadilateral which has an angle whose measure is unknown.

By definition, the sum of the interior angles of a quadrilateral is 360 degrees.

Knowing this, you can write the following equation:

24\°+100\°+78\°+x=360\°

Finally, you must solve for the angle "x" in order to calculate its measure.

This is:

24\°+100\°+78\°+x=360\°\\\\202\°+x=360\°\\\\x=360\°-202\°\\\\x=158\°

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help me please can someone please help i beg you. i have to say why this is wrong and solve this correctly. i beg you please
e-lub [12.9K]

Answer:

The person solving the problem first subtracted 6 from 15. Since the cube root is next to the six, the problem should be read as 15-6(\sqrt[3]{\frac{-1000}{27} } ) rather than (15-6)(\sqrt[3]{\frac{-1000}{27} } ).

  • To solve it correctly, first find the cube root of -1000/27: <u>-10/3</u>
  • Next, multiply by 6: -20
  • Finally, subtract from 15: 35

please lmk if anything is wrong with my answer, hope this helps :)

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3 years ago
PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!
pishuonlain [190]

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

  • \cos{\theta} = \pm \frac{2\sqrt{2}}{3}
  • \tan{\theta} = \pm \frac{\sqrt{2}}{4}

<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

\sin^{2}{\theta} + \cos^{2}{\theta} = 1

In this problem, we have that the sine is given by:

\sin{\theta} = \frac{1}{3}

Hence, applying the identity, the cosine is given as follows:

\cos^2{\theta} = 1 - \sin^2{\theta}

\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2

\cos^2{\theta} = 1 - \frac{1}{9}

\cos^2{\theta} = \frac{8}{9}

\cos{\theta} = \pm \sqrt{\frac{8}{9}}

\cos{\theta} = \pm \frac{2\sqrt{2}}{3}

The tangent is given by the sine divided by the cosine, hence:

\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}

\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}

\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}

\tan{\theta} = \pm \frac{\sqrt{2}}{4}

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

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Carmelo's employer matches 15% of carmelos contributions to his 401(k) plan. if carmelos employer contributed $300 to the plan l
Rzqust [24]
300 is 15% of 2000. The answer is $2000.
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The downtime per day for a computing facility has mean 4 hours and standard deviation .8 hour. Suppose that we want to compute p
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Answer:

1

Step-by-step explanation:

Given :

Mean, μ = 4

Standard deviation, s = 0.8

Sample size, n = 30

The distribution is independent.

Z = (x - μ) / s /sqrt(n)

Probability that downtime period is between 1 and 5

P(1≤ x ≤ 5) :

[(x - μ) / (s /sqrt(n))] ≤ Z ≤ [(x - μ) / (s /sqrt(n))]

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[-3 / 0.1460593] ≤ Z ≤] 1 / 0.1460593]

P(-20.539602 ≤ Z ≤ 6.8465342)

P(Z ≤ 6.8465342) - P(Z ≤ - 20.5396)

P(Z ≤ 6.8465342) = 1 (Z probability calculator)

P(Z ≤ - 20.5396) = 0 (Z probability calculator)

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-x on both sides to get
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