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Rama09 [41]
3 years ago
13

The density of a fish tank is 0.4 fish over feet cubed. There are 12 fish in the tank. What is the volume of the tank?Will fan a

nd Medal
Physics
1 answer:
Naddika [18.5K]3 years ago
4 0
<span>The answer is:  30 ft³ ;  or, write as:  30 cubic feet .
</span>________________________________________________________
Explanation: 
__________________________________________________
Given:
__________________________________________________
Density = 0.4 fish(es) per cubic foot (or, feet);
__________________________________________________
or, "Density = 0.4 fish / ft³ ;
__________________________________________________
And, given: "12 fish in the tank." ;
__________________________________________________
And Density = (value; in this case, "number of fish" / unit volume);

We are given:  Density, "D" = 0.4 fish / 1 ft³
______________________________________________
In our case, our volume is in "cubic ft." ; or, "ft³ ;
_______________________________________________
We want to find the actual volume of the tank (in "cubic feet"; or, " ft³ ");
_________________________________________________
 →  (1 ft³ / 0.4 fish) * 12 fish  = _____?  ft³ ?

 →  On the "left-hand side" of the equation; the units of "fish" cancel out to "1"; and we are left with units of "ft³ " ; which is the units for which we wish to solve.
_______________
  → So, so have  (1 ft³ * 12) / (0.4) = 12 ft³ / 0.4 = 30 ft³ .
___________________________________________________
<span>  → The answer is:  30 ft³ ;  or, write as:  30 cubic feet .</span>
_______________________________________________________
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In a crash test, a 2,500 kg car hits a concrete barrier at 13 m/s2 calculate the amount of force at which the car strikes the ba
Marta_Voda [28]

Answer:

32500N

Explanation:

Data obtained from the question include:

m (mass) = 2500 kg

a (acceleration) = 13 m/s2

F (force) =?

Force is the product of mass and acceleration. It is represented mathematically as:

Force = mass x acceleration

F = m x a

With the above formula, the force with which the car strikes the barrier can be obtained as follow:

F = m x a

F = 2500 x 13

F = 32500N

Therefore, the car will strike the barrier with a force of 32500N

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3 years ago
Calculate the separation between the two lowest levels for an O2 molecule in a one-dimensional container of length 5.0 cm. At wh
MariettaO [177]

Answer:

The separation between the two lowest levels =  1.24 * 10^{-39}J

The values of n where the energy of molecule reaches 1/2 kT at 300K = 2.2 * 10^{9}

The separation at this level = 1.8 * 10^{-30}J

Explanation:

Knowing the formula

En = \frac{n^{2} h^{2}  }{8 mL^{2} }

Mass of oxygen molecule

m (O2) = 32 amu * \frac{1.6605 * 10^{-27 kg} }{1 amu}

So the energy diference between the two lowest levels:

E2 - E1 = \frac{3h^{2} }{8mL^{2} }

E2 - E1 =  \frac{3 * (6.626 * 10^{-34} Js)^{2} } {8 * 32 amu * (\frac{1.6605 * 10^{-27 kg} }{1 amu})* (5*10^{-2})^{2}   } = 1.24 * 10^{-39}J

Now we should find n where the energy of molecule reaches 1/2 kT

En = \frac{n^{2} h^{2}  }{8 mL^{2} } = \frac{1}{2}kT

\frac{h^{2}  }{8 mL^{2} } = 4.13 * 10^{-14}J

n^{2} *  (4.13 * 10^{-14}J) = \frac{1}{2} (1.38 * 10^{-23}JK^{-1}) * 300K

n = 2.2 * 10^{9}

by the end is necessary to calculate the separation of the level

En - En-1 = (n^{2} - (n - 1)^{2}) * \frac{h^{2}  }{8 mL^{2} }

              = 1.8 * 10^{-30}J

4 0
3 years ago
A ball is rolled at a velocity of 25 m/sec. after 13.5 seconds, it comes to a stop . What is the acceleration of the ball?
nexus9112 [7]

Answer:

The answer to your question is a = -1.85 m/s² the acceleration is negative because it is coming to stop.

Explanation:

Data

vo = 25 m/s

t = 13.5 s

a= ?

vf = 0 m/s

Formula

vf = vo + at

solve for a

a = (vf - vo)/t

Substitution

a = (0 - 25) / 13.5

Simplification

a = -25/13.5

Result

a = -1.85 m/s²

8 0
3 years ago
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