Answer:
The velocity of the fish hitting the ground is , v = 45.795 m/s
Explanation:
Given data,
The mass of the fish, m = 5 kg
The height of the bird from the surface, h = 107 m
Using the III equation of motion,
v² = u² + 2gs
<em> v = √(u² + 2gs)</em>
Substituting the values,
v = √(0² + 2 x 9.8 x 107)
= 45.795 m/s
Hence, the velocity of the fish hitting the ground is, v = 45.795 m/s
Troposphere, stratosphere, mesosphere, thermosphere, exosphere
Hello Micu212006
Question: <span> Both the large loose rocks and the small loose rocks used to be part of earth's solid rock layer
</span><span>
Answer: True
Hope This Helps!
-Chris </span>
Answer: velocity of the car is 113.33m/s
Explanation:
From Doppler effect,
in the case which the source is moving towards the observer at rest
f2 = v/(v-vs) *f1
where f2 is the final observed frequency
f1 is the initial observed frequency
v = 340m/s (speed of sound in air)
vs = velocity of the source of sound.
rearranging the above equation
f2*(v - vs) = f1* v
vs = (f1* v/f2) - v
but f1 = 80Hz
f2 = 60Hz
v = 340m/s
substituting,
vs = (80 x 340)/60 - 340
vs = 453.33 - 340
vs = 113.33m/s
velocity of the car is 113.33m/s
Answer:
W=1705.2 J
Explanation:
Given that
mass ,m= 60 kg
Acceleration due to gravity ,g= 9.8 m/s²
Height ,h= 2.9 m
As we know that work done by a force given as
W = F . d
F=force
d=Displacement
W=work done by force
Now by putting the values
F= m g (Acting downward )
d= h (Upward)
W= m g h ( work done against the force)
W= 60 x 9.8 x 2.9 J
W=1705.2 J
Therefore the answer will be 1705.2 J.
