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lesya692 [45]
3 years ago
8

There is a single electron at a distance from the point charge. On which of the following quantities does the force on the elect

ron depend?
Check all that apply.
a. the distance between the positive charge and the electron
b. the charge on the electron
c. the mass of the electron
d. the charge of the positive charge
e. the mass of the positive charge
f. the radius of the positive charge
g. the radius of the electron
Physics
2 answers:
Anon25 [30]3 years ago
6 0

Answer:

The following situations apply: A, B, D.

Explanation:

The following situations apply: A, B, D.

1.) The electric force on the electron depends on A because E= F/q and thus, F=kqq_o/r^2 Ta. As you can see, the electric force depends on r^2, which is the distance between the positive charge and the negative charge, squared.

2.) As for B, the electric force on the electron depends on its charge as you can see from equation above.

3.) As for C, mass doesn't appear anyway in the equation for Force, thus, the mass doesn't matter.

4.) For D, yes, see equation for Force.

5.) For E, no

6.) For F, r in the equation for the force refers to the distance between both charges, not the radius of either charge. Thus, F doesn't matter.

7.) For G, no.

Debora [2.8K]3 years ago
4 0

Answer:

option (a), (b) and (d)

Explanation:

The force between the two charge particle is given by

F = \frac{KQq}{r^{2}}

Here, q is the charge of electron, = e

So, the force is

F = \frac{KQe}{r^{2}}

option (a), force depends on the distance between the positive charge and the electron.

option (b), force depends on the charge of electron.

option (c) force does not depend on the mass of electron.

option (d) force depends on the charge of positive charge.

option (e) force does not depend on the mass of positive charge.

option (f) force does not depend on the radius of positive charge.

option (g) force does not depend on the radius of electron.

OS, option (a), (b) and (d) are correct.

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Answer:

A: T = 120 N

B: T = 88.42 N

C: T = 70 N

Explanation:

Part A:

Since, the lighter bucket is supported by my had. So, the only unbalanced force in the system is the weight of heavier bucket. Hence, the tension in rope will be equal to the weight of heavier bucket.

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Part B:

This is the case where, two masses hang vertically on both sides of the pulley. To find the tension in such case we have the formula:

T = (2 m₁m₂g)/(m₁+m₂)

where,

m₁ = mass of heavier object = W₁/g = (120 N)/(9.8 m/s²) = 12.24 kg

m₁ = mass of lighter object = W₂/g = (70 N)/(9.8 m/s²) = 7.14 kg

g = 9.8 m/s²

Therefore,

T = [(2)(12.24 kg)(7.14 kg)(9.8 m/s²)]/(12.24kg + 7.14 kg)

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Part C:

Since, the heavier bucket is on ground. So, its weight is balanced by the normal reaction of the ground. The only unbalanced force in the system is the weight of lighter bucket. Hence, the tension in rope will be equal to the weight of lighter bucket.

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Answer:

n = 5 approx

Explanation:

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and

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e^n = \sqrt{\frac{h_1}{6.1} }\times \sqrt{\frac{h_2}{h_1} }\times... \sqrt{\frac{h_n}{h_{n-1} }

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3 years ago
Fiber optics are an important part of our modern internet. In these fibers, two different glasses are used to confine the light
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Answer:

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