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Oduvanchick [21]
3 years ago
15

How would this ratio be written as a fraction in simplest form? 24 to 4

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
5 0

Answer:

6 to 1

Step-by-step explanation:

4/2 is 2 and then divide that be 2 and its 1

24/2 is 12 and divide that by 2 and you get 6

marta [7]3 years ago
5 0

Answer:

6:1

Step-by-step explanation:

24:4

12:2

6:1

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Over the next 12 months you have to read more than 72 books. You have to read x books per month. The inequality 12x >72 repre
Lyrx [107]

Answer:

6 books per month

Step-by-step explanation:

books:months=books per month

5 0
3 years ago
Solve the following quadratic by completing the square.
lianna [129]

Answer:

x  = -5 \pm  \sqrt{26}

Step-by-step explanation:

x^2+10x-1=0\\\\\implies x^2+2\cdot 5 x +5^2-5^2-1=0\\\\\implies (x+5)^2-25-1=0\\\\\implies (x+5)^2 -26=0\\\\\implies (x+5)^2 = 26\\\\\implies x +5 = \pm\sqrt{26}\\\\\implies x  = -5 \pm  \sqrt{26}

4 0
2 years ago
Dave can clean pools at a constant rate of 3/5 pools/hours , What is the ratio of the number of pools to the number of hours?
mojhsa [17]

Answer:

The correct ratio for this is: 3:5.

Example:

If Dave had 10 hours to clean pools, how many would he be able to clean?

Answer: <u>Using the ratio 3.5,</u> Dave would be able to clean 6 pools in 10 hours.

Have a great day/night! ^^

3 0
2 years ago
HELP SMART PPL!!!!!!!!!!!!!!!!!
mezya [45]

Answer:

33.75

Step-by-step explanation:

45x0.75=33.75

3 0
3 years ago
In a sample of 1000 randomly selected consumers who had opportunities to send in a rebate claim form after purchasing a product,
Vadim26 [7]

Answer: 0.2872

Step-by-step explanation:

Given : In a sample of 1000 randomly selected consumers who had opportunities to send in a rebate claim form after purchasing a product, 260 of these people said they never did so.

i.e. n= 1000 and x= 260

⇒ Sample proportion : \hat{p}=\dfrac{260}{1000}=0.26

z-value for 95% confidence interval : z_c=1.960

Now, an upper confidence bound at the 95% confidence level for the true proportion of such consumers who never apply for a rebate. :-

\hat{p}+ z_c\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

=0.26+ (1.96)\sqrt{\dfrac{0.26(1-0.26)}{1000}}

=0.26+ (1.96)(0.01387)=0.26+0.0271852=0.2871852\approx0.2872

∴ An upper confidence bound at the 95% confidence level for the true proportion of such consumers who never apply for a rebate : 0.2872

7 0
3 years ago
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