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3 years ago

7+2x/3=5 im stuck on this question pls hhelp my homework is due soon pls help

Mathematics

1 answer:

faltersainse [42]3 years ago

8 0

The value of X is 4

please see the attached picture for full solution

Hope it helps

Good luck on your assignment..

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Simplify the product using the distributive property. Please show your

shtirl [24]

Answer:

9h² + 51h + 28

Step-by-step explanation:

(5h + 4)(4h + 7)

=> 9h² + 35h + 16h + 28

=> 9h² + 51h + 28

Therefore, 9h² + 51h + 28 is the simplified expression.

Hoped this helped.

5 0

2 years ago

Read 2 more answers

The center of a circle is at (−2, −7) and its radius is 6.

abruzzese [7]

The correct option is C

8 0

3 years ago

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If the graph of y=f(x) passes through the point (0,1), and dy/dx=xsin(x^2)/y, then f(x)= ?

Zigmanuir [339]

The differential equation

dy/dx = x sin(x ²) / y

is separable as

y dy = x sin(x ²) dx

Integrate both sides:

∫ y dy = ∫ x sin(x ²) dx

∫ y dy = 1/2 ∫ 2x sin(x ²) dx

∫ y dy = 1/2 ∫ sin(x ²) d(x ²)

1/2 y ² = -1/2 cos(x ²) + C

Solve for y implicitly:

y ² = -cos(x ²) + C

Given that y = 1 when x = 0, we get

1² = -cos(0²) + C

1 = -cos(0) + C

1 = -1 + C

C = 2

Then the particular solution to the DE is

y ² = 2 - cos(x ²)

Solving explicitly for y would give two solutions,

y = ± √(2 - cos(x ²))

but only the one with the positive square root satisfies the initial condition:

√(2 - cos(0²)) = √1 = 1

-√(2 - cos(0²)) = -√1 = -1 ≠ 1

So the unique solution to this DE is

y = √(2 - cos(x ²))

4 0

2 years ago

Part B

NARA [144]

Answer:

All of them work.

Step-by-step explanation:

Part D stated any number can be put and the equation will still be the same. I already answered this question for another guy and tou can go search for that if you want to see edmentums sample answer that states they all work.

6 0

3 years ago

Solving Quadratic Equations using the Square Root Property

Afina-wow [57]

Answer:

$x = -2$ or $x = -5$

Step-by-step explanation:

You need to complete the square before you can take the square root of both sides.

$x^2 + 7x + 10 = 0$

Subtract 10 from both sides.

$x^2 + 7x = -10$

To complete the square, you need to add the square of half of the x-term coefficient to both sides.

The x-term coefficient is 7. Half of that is 7/2. Square it to get 49/4. Now we add 49/4 to both sides of the equation.

$x^2 + 7x + \dfrac{49}{4} = -10 + \dfrac{49}{4}$

$(x + \dfrac{7}{2})^2 = -\dfrac{40}{4} + \dfrac{49}{4}$

$(x + \dfrac{7}{2})^2 = \dfrac{9}{4}$

Now we use the square root property, if

$x^2 = k$ , then

$x = \pm \sqrt{k}$

$x + \dfrac{7}{2} = \pm \sqrt{\dfrac{9}{4}}$

$x + \dfrac{7}{2} = \pm \dfrac{3}{2}$

$x + \dfrac{7}{2} = \dfrac{3}{2}$ or $x + \dfrac{7}{2} = -\dfrac{3}{2}$

$x = -\dfrac{4}{2}$ or $x = -\dfrac{10}{2}$

$x = -2$ or $x = -5$

5 0

3 years ago