Answer:
6+x with x equalling the amount of coins bought if that is what you were looking for
Step-by-step explanation:
if you want to make and equation out of this you don't know the amount of coins she bought so you use a variable (x) to replace that unknown number then since it says she bought more she is adding more to her collection which means it would be an addition problem, leaving you with 6+x for your final answer
Answer:
blue marbles - 2/9. red marbles - 3/9 = 1/3 clear marbles - 4/9. Davis got a 2/9 chance and Tessa got a 2/8 or 1/4 chance. I don't know about the last question. it might be 5/9 but I don't know sorry.
To model this situation, we are going to use the exponential function:

where

is the initial number of cars

is the growing rate in decimal form

is number of tames the growing rate is increasing per year

is the time in years
To convert the growing rate to decimal form, we are going to divide the rate by 100%


Since the growing rate is increasing quarterly,

. We also know that the initial number of cars is 920, so

. Lets replace all those values in our function:



We can conclude that:
Rate ---------> The quarterly rate of growth is 0.03 or 3%
Exponent --------> The compound periods multiplied by the number of years is 4t
Coefficient--------> The initial number of cars serviced is 920
Base------> The growth factor is represented by 1.03
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an
S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d] → Equation (1)
S=an+an−1+an−2+an−3+...+a1
S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d] → Equation (2)
Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)
2S=n(a1+an)
S=n/2(a1+an)
Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
Answer:
The answer simplify is 16384
Step-by-step explanation: