Ask question

Ask question

All categories

2 years ago

12

Is 0.09 more or less than 0.9? same with 0.06 and 0.6.

2 answers:

In-s [12.5K]2 years ago

8 0

.09 is less than 0.9.

ArbitrLikvidat [17]2 years ago

5 0

0.9 is greater than 0.09

You might be interested in

Simplify -2 (4+b+6)-6 (3d-5)

VLD [36.1K]

-2(4+b+6)-6(3d-5

-8-2b-12-18d+30

10-2b-18d

Hope this helped!

-Twixm

3 0

3 years ago

Read 2 more answers

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

2 years ago

According to his running log, Reid averaged 4 miles per week and 6 miles per week this month. By what percent has his average in

Bas_tet [7]

Answer:

24 cause u take 4 time 6 is 24 u got ya answer

6 0

3 years ago

Sean bought a 6 inch sub. He ate 3 3/4 inches. How much sub does he have left in the simplest form.

irinina [24]

Answer: 2 1/2

hope this helps

4 0

2 years ago

Can someone help with my homework please

Ivanshal [37]

It would be letter A.

6 0

3 years ago

Read 2 more answers