4 years ago

How resolve this equation 2x^2-3x-y=-5 -x+y=5

1 answer:

7 0

$-x+y=5\Rightarrow y=x+5$

Substitute $y$ in the other equation:
$2x^{2}-3x-(x+5)=-5$
$\Rightarrow 2x^{2}-3x-x-5=-5$
$\Rightarrow 2x^{2}-4x-5=-5$
$\Rightarrow 2x^{2}-4x=0$
$\Rightarrow 2x(x-2)=0$

So either
$2x=0\Rightarrow x=0\Rightarrow y=0+5=5$
or
$x-2=0\Rightarrow x=2\Rightarrow y=2+5=7$

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The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 1 2 3 4 . A rot

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I found the corresponding image. Pls. see attachment.

<span>The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 2 (translation and rotation).

A rotation translation must be used to make the two polygons coincide.

A sequence of transformations of polygon ABCDE such that ABCDE does not coincide with polygon FGHIJ is a translation 2 units down and a 90° counterclockwise rotation about point D </span>