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stich3 [128]
3 years ago
9

How resolve this equation 2x^2-3x-y=-5 -x+y=5

Mathematics
1 answer:
Lelechka [254]3 years ago
7 0
-x+y=5\Rightarrow y=x+5

Substitute y in the other equation:
2x^{2}-3x-(x+5)=-5
\Rightarrow 2x^{2}-3x-x-5=-5
\Rightarrow 2x^{2}-4x-5=-5
\Rightarrow 2x^{2}-4x=0
\Rightarrow 2x(x-2)=0

So either
2x=0\Rightarrow x=0\Rightarrow y=0+5=5
or
x-2=0\Rightarrow x=2\Rightarrow y=2+5=7
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