<em>90</em> and all of its multiples are.
Answer:
The answer is option A) <em>r</em><em> </em>and <em>s</em>
<span>T = 3U / E solve for U
3U = T * E
U = (</span>T * E)/3
U = 1/3(TE)
Let volume of 4% solution = x and of 14% be y
them x + y = 65........(1) also using the actual weights of salt:-
0.04x + 0.14y = 65*0.06 = 3.9
multiplying the above equation by -25 we have
-x - 3.5y = -97.5 adding this to equation (1)
--2.5y = -32.5
y= 13
and x = 65 - 13 = 52
so we need 13 mls of the 14%, and 52 mls of the 4% solution.
