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2 years ago

3. In a 32-bit CPU, the largest integer that we can store is 2147483647. Verify this with a

Computers and Technology

1 answer:

Semenov [28]2 years ago

5 0

Answer:

No, it can't be verified with a pseudocode.

Explanation:

We can not verify this with a pseudocode because the largest integer that we can store in 32-bit integer goes by the formula 2^32 - 1 = 4, 294, 967,295 and this means that it has 32 ones. Or it may be 2^31 - 1 = 2, 147, 483,647 which is a two complement signed integer.

Despite the fact that it can not be verified by using pseudocode, we can do the Verification by writting programs Through some programming language or in plain English code.

In a 32-bit CPU, the largest integer that we can store is 2147483647 because we can store integer as 2^31 and - (2^31 + 1).

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The loop function is similar to range(), but handles the parameters somewhat differently: it takes in 3 parameters: the starting

nexus9112 [7]

Answer and Explanation:

def loop(start, stop, step):

return_string = ""

if step == 0:

step = 1

if start > stop: # the bug was here, fixed it

step = abs(step) * -1

else:

step = abs(step)

for count in range(start, stop, step):

return_string += str(count) + " "

return return_string.strip()

5 0

3 years ago

More registers appear to be a good thing, in terms of reducing the total number of memory accesses a program might require. Give

gulaghasi [49]

Answer:

Following is given the answer step by step:

Explanation:

First of all we will write a program using MARIE that will support the statement: Sum = (A + B) - (C + D). All the necessary comments are given in front of each statement:

Load A # variable A will be loaded

Add B # B will be added to A

Store Temp1 # A + B will be stored in Temp1

Load C # C will be loaded in memory

Add D # D will be added to C

Store Temp2 # C + D will ge stored in Temp2

Load Temp1 # Temp1 will be loaded in the memory

Subt Temp2 # Temp2(A + B) get subtracted from Temp1(A - B)

Store Sum # (A + B) - (C + D) will get stored in Sum.

We can see from above program that memory is accessed 9 times. While if C + D get executed first than memory accesses will be reduced to 7.

Above same program could be written using an architecture of 4 registers:

The program is as follows:

Load R1 , A #A will be loaded into R1

Load R2 , B # B will be loaded into R2

Add R1 , R2 # R2 gets added to R1 and the result is stored in R1 (A + B)

Load R3 , C # C loaded into R3

Load R4 , D # D loaded into R4

Add R3 , R4 # Value in R4 gets added into R3 and R3 becomes (C + D)

#no memory accesses required for this operation

Subt R1 , R4 #R4 (C + D) gets subtracted from R1 (A + B)

#no memory accesses required for this operation

Store Sum # The recent value will be stored into Sum

Here memory is accessed 5 times in total.

8 0

3 years ago

Import java.awt.GridLayout;

Vikki [24]

Answer:

public class ConversionCalculator extends JFrame {

private JLabel inch_Label, meter_Label, cm_Label, yard_Label;

private JButton clear, calculate, exit;

private JTextField inch_tf, cm_tf, meters_tf, yards_tf;

public ConversionCalculator()

{

exitButtonHandler exitB;

clearButtonHandler clearB;

calcButtonHandler calcB;

setTitle("Conversion Calculator");

setSize(600,200);

setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);

//The first layout we use will be 1 row with three columns

setLayout(new GridLayout(1,3));

//initialize all the components

inch_Label = new JLabel("Inches");

meter_Label = new JLabel("Meters");

cm_Label = new JLabel("Centimeters");

yard_Label = new JLabel("Yards");

clear = new JButton("Clear");

calculate = new JButton("Calculate");

exit = new JButton("Exit");

inch_tf = new JTextField("0.00");

cm_tf = new JTextField("0.00");

meters_tf = new JTextField("0.00");

yards_tf = new JTextField("0.00");

JPanel panel1 = new JPanel();

panel1.setLayout(new GridLayout(2,2));

JPanel panel2 = new JPanel();

panel2.setLayout(new GridLayout(2,2));

JPanel panel3 = new JPanel();

panel3.setLayout(new GridLayout(3,1));

panel1.add(cm_Label);

panel1.add(cm_tf);

panel1.add(meter_Label);

panel1.add(meters_tf);

panel2.add(inch_Label);

panel2.add(inch_tf);

panel2.add(yard_Label);

panel2.add(yards_tf);

panel3.add(clear);

panel3.add(calculate);

panel3.add(exit);

add(panel1);

add(panel2);

add(panel3);

exitB = new exitButtonHandler();

exit.addActionListener(exitB);

clearB = new clearButtonHandler();

clear.addActionListener(clearB);

calcB = new calcButtonHandler();

calculate.addActionListener(calcB);

setVisible(true);

}

//public static void main(String[] args)

// {

// new ConversionCalculator();

//}

private class exitButtonHandler implements ActionListener

{

public void actionPerformed(ActionEvent e)

{

//exits program

System.exit(0);

}

private class clearButtonHandler implements ActionListener

{

public void actionPerformed(ActionEvent e)

{

//clear button sets all text fields to 0

inch_tf.setText("0.00");

meters_tf.setText("0.00");

yards_tf.setText("0.00");

cm_tf.setText("0.00");

}

private class calcButtonHandler implements ActionListener

{

public void actionPerformed(ActionEvent e)

{

double inches, yards, meters, cms;

DecimalFormat df = new DecimalFormat("0.00");

//parse strings in textbox into doubles

inches = Double.parseDouble(inch_tf.getText());

yards = Double.parseDouble(yards_tf.getText());

meters = Double.parseDouble(meters_tf.getText());

cms = Double.parseDouble(cm_tf.getText());

//we check which value has been tampered with and base our conversion off this

//because of this it is important that the user clears, or else it will do inch conversion

if(inches != 0.00)

{

cms = inches * 2.54;

meters = cms / 100;

yards = inches / 36;

cm_tf.setText(df.format(cms));

meters_tf.setText(df.format(meters));

yards_tf.setText(df.format(yards));

}

else if(yards != 0.00)

{

inches = yards / 36;

cms = inches * 2.54;

meters = cms / 100;

cm_tf.setText(df.format(cms));

meters_tf.setText(df.format(meters));

inch_tf.setText(df.format(inches));

}

else if(meters != 0.00)

{

cms = meters * 100;

inches = cms / 2.54;

yards = inches / 36;

cm_tf.setText(df.format(cms));

inch_tf.setText(df.format(inches));

yards_tf.setText(df.format(yards));

}

else if(cms != 0.00)

{

inches = cms / 2.54;

yards = inches / 36;

meters = cms / 100;

meters_tf.setText(df.format(meters));

inch_tf.setText(df.format(inches));

yards_tf.setText(df.format(yards));

}

Explanation:

Inside the action performed method, pass the strings in text box.
check if the value has been modified then do the relevant conversions inside the conditional statement.
When the user clears, it will not do to the inch conversion.

8 0

3 years ago

According to Amdahl's Law, what is the speedup gain for an application that is 60% parallel and we run it on a machine with 4 pr

rodikova [14]

With four processing cores, we get a speedup of 1.82 times.

<h3>What is Amdahl's Law?</h3>

Amdahl's law exists as a formula that provides the theoretical speedup in latency of the implementation of a task at a fixed workload that can be expected of a system whose resources exist improved.

Amdahl's law exists that, in a program with parallel processing, a relatively few instructions that hold to be completed in sequence will have a limiting factor on program speedup such that adding more processors may not complete the program run faster.

Amdahl's law stands also known as Amdahl's argument. It is utilized to find the maximum expected progress to an overall system when only part of the system exists improved. It is often utilized in parallel computing to indicate the theoretical maximum speed up utilizing multiple processors.

Hence, With four processing cores, we get a speedup of 1.82 times.

To learn more about Amdahl's Law refer to:

brainly.com/question/16857455

#SPJ4

6 0

1 year ago

Many contemporary languages allow two kinds of comments: one in which delimiters are used on both ends (multiple-line comments),

m_a_m_a [10]

Answer and Explanation:

Multiple-line comments :

Advantage :In the event that we need to remark out of zone of the given program , we can utilize it.

Disadvantage : In numerous line results are in reduced unwavering quality. It stretches out the remark as far as possible of the following comment.For least difficult approach to unintentionally leave off the last delimiter, which successfully expelling code from the program.

Single Line Comments :

Advantage :In the event that you need to close all the delimiter before close the program we utilize this kind of remarks.

Disadvantage : It put more burden on your program .It repeated on every line of a block of comments

3 0

2 years ago