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lapo4ka [179]
2 years ago
5

What is the value of the expression 12-15÷3+9 ?

Mathematics
1 answer:
satela [25.4K]2 years ago
7 0
12 - 15 ÷ 3 + 9

Following BODMAS = Bracket Order Division Multiplication Addition Subtraction

Division comes before Addition and Subtraction, so we carry out Division first.

12 - 15 ÷ 3 + 9,                15 ÷ 3 = 5

12 - 5 + 9                   

7 + 9

16

I hope you find this explanation useful.
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We know the following about the numbers a, b and c:
labwork [276]

Step-by-step explanation:

(a + b)² = 9

(b + c)² = 25

(a + c)² = 81

Taking the square root:

a + b = ±3

b + c = ±5

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By adding these three equations together and dividing both sides by 2, we get the value of a + b + c.

Possible combinations for a + b + c such that the sum is greater than or equal to 1 are:

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2 years ago
Colin is working to earn some money for a new CD player. On Saturday he earns half as much as he did on Sunday, but twice as muc
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Answer:

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3 0
3 years ago
7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?
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Answer: a. Radius of circle = \sqrt{85}

b. The equation of this circle : (x-3)^2+(y-10)^2=85

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = \sqrt{(12-3)^2+(12-10)^2}

Radius of circle = \sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}

i.e. Radius of circle = \sqrt{85}

b. Equation of a circle = (x-h)^2+(y-k)^2=r^2 , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= \sqrt{85} , we get

(x-3)^2+(y-10)^2=(\sqrt{85})^2

(x-3)^2+(y-10)^2=85

∴  The equation of this circle :(x-3)^2+(y-10)^2=85

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3 years ago
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