P(odd) or P(multiple of 5)
When we roll 2 number cubes
all possible outcomes of their sum are 2,3,4,5,6,7,8,9,10,11,12.(11 possible outcomes)
Out of those possible outcomes
3,5,7,9,11 are odd (5 outcomes) and ...
5 and 10 are multiples of 5 (2 outcomes)
Now, P(odd) or P(multiple of 5) really means P(odd) + P (multiple of 5) =
(If we had “and” instead of “or” we multiply)
= (5/11) +(2/11)
=7/11
hdhdbbdnfnbrndjjrhrhrhrhbdbd
Answer:
Ummm -6 and -4
Step-by-step explanation:
Duh
Solve for m:C = 1/3 π d^2 m
C = 1/3 d^2 m π is equivalent to 1/3 d^2 m π = C:1/3 π d^2 m = C
Divide both sides by (π d^2)/3:Answer: m = (3 C)/(π d^2)
